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JohnCarney111

  • 2 years ago

I need help *** if someone can get back to me you will get a medal!! really need help lost

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  1. amistre64
    • 2 years ago
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    Post the question you need help with, and not an advertisement to "swap answers" please

  2. lexiamee
    • 2 years ago
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    what quiz

  3. JohnCarney111
    • 2 years ago
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    ok for the function 32 over x+3 find (g^-1*g(5)

  4. JohnCarney111
    • 2 years ago
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    Graphing Radical Functions Quiz '

  5. amistre64
    • 2 years ago
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    what is the value of g(5)?

  6. JohnCarney111
    • 2 years ago
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    Sorry it soupposed to be (g^-1*g)(5)

  7. lexiamee
    • 2 years ago
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    I dont remeber that, srry I take Geometry and Id ont rmeber how to solve

  8. JohnCarney111
    • 2 years ago
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    it does not say what g equals

  9. amistre64
    • 2 years ago
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    im pretty sure g is the name of the function they gave you

  10. amistre64
    • 2 years ago
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    \[g(x)=\frac{32}{x+3}\]

  11. JohnCarney111
    • 2 years ago
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    ok so i multiply that funtion by itself to the -1 power?

  12. amistre64
    • 2 years ago
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    the -1 notation here denotes the inverse of the function .. not really a power

  13. amistre64
    • 2 years ago
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    do you know how to find an inverse?

  14. JohnCarney111
    • 2 years ago
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    not really

  15. amistre64
    • 2 years ago
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    given a function \[y=\frac{32}{x+3}\] the inverse swapps x and y, so the inverse of this is \[x=\frac{32}{y+3}\]

  16. JohnCarney111
    • 2 years ago
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    so now i divide?

  17. amistre64
    • 2 years ago
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    lets work the inverse a little more .. just so things loook normal \[x=\frac{32}{y+3}\] \[y+3=\frac{32}{x}\] \[y=\frac{32}{x}-3=g^{-1}(x)\]

  18. amistre64
    • 2 years ago
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    so, \[g^{-1}*g=(\frac{32}x-3)(\frac{32}{x+3})\] plug in x=5 and find the product

  19. JohnCarney111
    • 2 years ago
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    4

  20. JohnCarney111
    • 2 years ago
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    now what? would i times 4 by 5?

  21. amistre64
    • 2 years ago
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    not if your following what ive written ....

  22. JohnCarney111
    • 2 years ago
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    the answer choices are 11 5 2 and 1 so ???

  23. JohnCarney111
    • 2 years ago
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    what now

  24. JohnCarney111
    • 2 years ago
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    sorry i am not good at this

  25. amistre64
    • 2 years ago
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    hmm, you sure thats a "*" in between them or is it more of an "\(^o\)"

  26. JohnCarney111
    • 2 years ago
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    an o

  27. amistre64
    • 2 years ago
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    ahhh, that changes things, the open "o" means a composite, not a multiplication of the 2 of them

  28. amistre64
    • 2 years ago
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    g^(-1) o g has a property that the input is the same as the output

  29. lexiamee
    • 2 years ago
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    could you check out the math chat box it may need to be controlled.

  30. amistre64
    • 2 years ago
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    it needs the adminstrators to come online and deal with the isp itself .. so that the whole school gets banned

  31. amistre64
    • 2 years ago
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    so if the input is 5, what is the output?

  32. JohnCarney111
    • 2 years ago
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    5?

  33. JohnCarney111
    • 2 years ago
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    -5

  34. amistre64
    • 2 years ago
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    yes, if the input is 5, the output is 5 ... its a special property of composing inverses of each other

  35. lexiamee
    • 2 years ago
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    what school. Cant you bn them if they need

  36. JohnCarney111
    • 2 years ago
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    so if there is an o don't multiply make input sam as output?

  37. amistre64
    • 2 years ago
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    only if the functions are inverses of each other does that work. If they are not inverses the input and output can be different

  38. JohnCarney111
    • 2 years ago
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    brb domestic situation at house have to help brother

  39. amistre64
    • 2 years ago
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    good luck ::)

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