DLS
  • DLS
x^3+y^3+3axy=0 dy/dx=?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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DLS
  • DLS
\[\LARGE 3x^{2}+3y^{2} \frac{dy}{dx}-3ax=0\] this gives..finally.. \[\LARGE \frac{dy}{dx}=\frac{x(a-x)}{y^{2}} \] I doubt this because im quite unsure about the derivative of 3axy,we are differentiating wrt x or y? if its x then 3ay(dx//dx) not sure..
DLS
  • DLS
@hartnn
hartnn
  • hartnn
you'll need product rule for 3axy

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DLS
  • DLS
I thought product rule was used for function times function
DLS
  • DLS
thats a variable,isn't it
hartnn
  • hartnn
y is the function of x, x is the function of x.
DLS
  • DLS
:O
hartnn
  • hartnn
(xy)' = x'y+xy' = y+xy'
DLS
  • DLS
so how will we find for 3axy?
hartnn
  • hartnn
3a (y+xy')
DLS
  • DLS
\[\LARGE 3ay(\frac{dx}{dx}) |||| 3ax(\frac {dy}{dx}) \]
hartnn
  • hartnn
dx/dx=1
DLS
  • DLS
yeah!
hartnn
  • hartnn
and i assume ||| is +
DLS
  • DLS
yes
DLS
  • DLS
thats it?:O
hartnn
  • hartnn
so, dy/dx will change..
DLS
  • DLS
what do u mean?
hartnn
  • hartnn
i mean recalculate dy/dx
DLS
  • DLS
\[\LARGE \frac{dy}{dx}= \frac{-3(ay+x^{2})}{3(y^{2}-ax)} \]
hartnn
  • hartnn
-ax ?
DLS
  • DLS
sorry + printing mistake :P
hartnn
  • hartnn
then ok.
DLS
  • DLS
:D

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