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I have to solve the system
7x  3y = 20
5x + 3y = 16
I solved it once;
7x  3y = 20
+ 5x + 3y = 16
= 12x = 36
= x = 3
7(3) = 3y = 20
= 21  3y = 20
21  21  3y = 21  21
= 3y = 1
= y = 1/3
so (3, 1/3)
But I cant figure out how to solve it for a nother way and get the same answer.
 one year ago
 one year ago
I have to solve the system 7x  3y = 20 5x + 3y = 16 I solved it once; 7x  3y = 20 + 5x + 3y = 16 = 12x = 36 = x = 3 7(3) = 3y = 20 = 21  3y = 20 21  21  3y = 21  21 = 3y = 1 = y = 1/3 so (3, 1/3) But I cant figure out how to solve it for a nother way and get the same answer.
 one year ago
 one year ago

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FZ6628Best ResponseYou've already chosen the best response.0
Example: 2X+6Y=10 3X2Y=12 There is another method called substitution, in which you manipulate one of the equation to isolate a variable. For example 2X+6Y=10 can be manipulated into X=53Y Then you substitute the second part of the equation, 53Y in the second equation, 3X2Y=12, resulting in 3(53Y)2Y=12. Then you can use simple algebra to figure out X and Y
 one year ago

anonnnnBest ResponseYou've already chosen the best response.0
I know about substitution, and I have attempted it several times in several different manners but I cannot come up with the same answer as the first.
 one year ago

HeroBest ResponseYou've already chosen the best response.0
There's at least five different ways of solving these 1. Graphing 2. Substitution 3. Elimination 4. Matrices 5. Cramer's Method Pick one
 one year ago

HeroBest ResponseYou've already chosen the best response.0
There's also slopeintercept method as well
 one year ago
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