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UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0\[y=\frac{2x}{x^21}\] \[y=\frac{2x}{(x1)(x+1)}\] the function will be zero at x=0 so there will be asymptotes at \[x=\pm1\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.0when \(0<< x\) (x is a large positive number) the numerator will be large and positive, but the denominator much larger and will dominate, and hence the function will be small when \(x<<0\) (x is large negative number) the numerator will be negative and large, but the denominator will again dominate and hence the function will be small and negative
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