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Garcia_123
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*PLEASE HELP*!!COIN IS TOSSED UPWARD FROM A BALCONY 188FT HIGH WITH AN INITIAL VELOCITY OF 32FT PER SEC. THE HEIGHT OF THE COIN, IN FT AFTER "T" SECONDS IS GIVEN BY FUNCTION h(t)=16^2+32+188. FOR WHAT LENGTH OF TIME WILL THE COIN BE AT THE HEIGHT OF AT LEAST 60 FT?
 one year ago
 one year ago
Garcia_123 Group Title
*PLEASE HELP*!!COIN IS TOSSED UPWARD FROM A BALCONY 188FT HIGH WITH AN INITIAL VELOCITY OF 32FT PER SEC. THE HEIGHT OF THE COIN, IN FT AFTER "T" SECONDS IS GIVEN BY FUNCTION h(t)=16^2+32+188. FOR WHAT LENGTH OF TIME WILL THE COIN BE AT THE HEIGHT OF AT LEAST 60 FT?
 one year ago
 one year ago

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vacationeer Group TitleBest ResponseYou've already chosen the best response.0
where are the "T's" in the equation?
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
cuz right now with what you have... it would just be.... 476 no matter what... which is impossible
 one year ago

Garcia_123 Group TitleBest ResponseYou've already chosen the best response.0
That's all the info i have. I have the answer which is 0 sec to 4 sec but not sure how they got that.
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
O.o.......i mean the equation would work better if it was lik \[h(t)=16(T^{2})+32T+188\]
 one year ago

mandonut Group TitleBest ResponseYou've already chosen the best response.0
find time at max height
 one year ago

mandonut Group TitleBest ResponseYou've already chosen the best response.0
take the first dervivative
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
that would make more sense... in which you would substitute h(t) for 60 and then solve from there
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
@mandonut ..... its not a max question... its asking for the position of the ball
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
so then it would be \[60=16(T^{2})+32T+188\]
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
pull the 60 over to get.... \[0=16(T^{2}) +32T +128\]
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
now you can take out 16 from the whole equation to get.... \[0=T^{2}+2T+8\]
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
of which can turnn into ..... \[0=(T+4)(T+2)\]
 one year ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
so then T={4,2} since you're dealing with only positive time (as time usually can only be positive)... you get T=4
 one year ago

Garcia_123 Group TitleBest ResponseYou've already chosen the best response.0
thanks!
 one year ago
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