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where are the "T's" in the equation?

cuz right now with what you have... it would just be.... 476 no matter what... which is impossible

O.o.......i mean the equation would work better if it was lik \[h(t)=-16(T^{2})+32T+188\]

find time at max height

take the first dervivative

that would make more sense... in which you would substitute h(t) for 60 and then solve from there

*coin

so then it would be \[60=-16(T^{2})+32T+188\]

pull the 60 over to get.... \[0=-16(T^{2}) +32T +128\]

now you can take out 16 from the whole equation to get....
\[0=-T^{2}+2T+8\]

of which can turnn into ..... \[0=(-T+4)(T+2)\]

thanks!