Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

Garcia_123

  • 2 years ago

*PLEASE HELP*!!COIN IS TOSSED UPWARD FROM A BALCONY 188FT HIGH WITH AN INITIAL VELOCITY OF 32FT PER SEC. THE HEIGHT OF THE COIN, IN FT AFTER "T" SECONDS IS GIVEN BY FUNCTION h(t)=-16^2+32+188. FOR WHAT LENGTH OF TIME WILL THE COIN BE AT THE HEIGHT OF AT LEAST 60 FT?

  • This Question is Closed
  1. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    where are the "T's" in the equation?

  2. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    cuz right now with what you have... it would just be.... 476 no matter what... which is impossible

  3. Garcia_123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    That's all the info i have. I have the answer which is 0 sec to 4 sec but not sure how they got that.

  4. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    O.o.......i mean the equation would work better if it was lik \[h(t)=-16(T^{2})+32T+188\]

  5. mandonut
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    find time at max height

  6. mandonut
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    take the first dervivative

  7. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    that would make more sense... in which you would substitute h(t) for 60 and then solve from there

  8. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @mandonut ..... its not a max question... its asking for the position of the ball

  9. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    *coin

  10. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so then it would be \[60=-16(T^{2})+32T+188\]

  11. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    pull the 60 over to get.... \[0=-16(T^{2}) +32T +128\]

  12. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    now you can take out 16 from the whole equation to get.... \[0=-T^{2}+2T+8\]

  13. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    of which can turnn into ..... \[0=(-T+4)(T+2)\]

  14. vacationeer
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so then T={4,-2} since you're dealing with only positive time (as time usually can only be positive)... you get T=4

  15. Garcia_123
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks!

  16. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.