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Garcia_123
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*PLEASE HELP*!!COIN IS TOSSED UPWARD FROM A BALCONY 188FT HIGH WITH AN INITIAL VELOCITY OF 32FT PER SEC. THE HEIGHT OF THE COIN, IN FT AFTER "T" SECONDS IS GIVEN BY FUNCTION h(t)=16^2+32+188. FOR WHAT LENGTH OF TIME WILL THE COIN BE AT THE HEIGHT OF AT LEAST 60 FT?
 2 years ago
 2 years ago
Garcia_123 Group Title
*PLEASE HELP*!!COIN IS TOSSED UPWARD FROM A BALCONY 188FT HIGH WITH AN INITIAL VELOCITY OF 32FT PER SEC. THE HEIGHT OF THE COIN, IN FT AFTER "T" SECONDS IS GIVEN BY FUNCTION h(t)=16^2+32+188. FOR WHAT LENGTH OF TIME WILL THE COIN BE AT THE HEIGHT OF AT LEAST 60 FT?
 2 years ago
 2 years ago

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vacationeer Group TitleBest ResponseYou've already chosen the best response.0
where are the "T's" in the equation?
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
cuz right now with what you have... it would just be.... 476 no matter what... which is impossible
 2 years ago

Garcia_123 Group TitleBest ResponseYou've already chosen the best response.0
That's all the info i have. I have the answer which is 0 sec to 4 sec but not sure how they got that.
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
O.o.......i mean the equation would work better if it was lik \[h(t)=16(T^{2})+32T+188\]
 2 years ago

mandonut Group TitleBest ResponseYou've already chosen the best response.0
find time at max height
 2 years ago

mandonut Group TitleBest ResponseYou've already chosen the best response.0
take the first dervivative
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
that would make more sense... in which you would substitute h(t) for 60 and then solve from there
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
@mandonut ..... its not a max question... its asking for the position of the ball
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
so then it would be \[60=16(T^{2})+32T+188\]
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
pull the 60 over to get.... \[0=16(T^{2}) +32T +128\]
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
now you can take out 16 from the whole equation to get.... \[0=T^{2}+2T+8\]
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
of which can turnn into ..... \[0=(T+4)(T+2)\]
 2 years ago

vacationeer Group TitleBest ResponseYou've already chosen the best response.0
so then T={4,2} since you're dealing with only positive time (as time usually can only be positive)... you get T=4
 2 years ago
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