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anonymous
 3 years ago
*PLEASE HELP*!!COIN IS TOSSED UPWARD FROM A BALCONY 188FT HIGH WITH AN INITIAL VELOCITY OF 32FT PER SEC. THE HEIGHT OF THE COIN, IN FT AFTER "T" SECONDS IS GIVEN BY FUNCTION h(t)=16^2+32+188. FOR WHAT LENGTH OF TIME WILL THE COIN BE AT THE HEIGHT OF AT LEAST 60 FT?
anonymous
 3 years ago
*PLEASE HELP*!!COIN IS TOSSED UPWARD FROM A BALCONY 188FT HIGH WITH AN INITIAL VELOCITY OF 32FT PER SEC. THE HEIGHT OF THE COIN, IN FT AFTER "T" SECONDS IS GIVEN BY FUNCTION h(t)=16^2+32+188. FOR WHAT LENGTH OF TIME WILL THE COIN BE AT THE HEIGHT OF AT LEAST 60 FT?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0where are the "T's" in the equation?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0cuz right now with what you have... it would just be.... 476 no matter what... which is impossible

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That's all the info i have. I have the answer which is 0 sec to 4 sec but not sure how they got that.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0O.o.......i mean the equation would work better if it was lik \[h(t)=16(T^{2})+32T+188\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0find time at max height

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0take the first dervivative

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that would make more sense... in which you would substitute h(t) for 60 and then solve from there

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mandonut ..... its not a max question... its asking for the position of the ball

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so then it would be \[60=16(T^{2})+32T+188\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0pull the 60 over to get.... \[0=16(T^{2}) +32T +128\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now you can take out 16 from the whole equation to get.... \[0=T^{2}+2T+8\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0of which can turnn into ..... \[0=(T+4)(T+2)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so then T={4,2} since you're dealing with only positive time (as time usually can only be positive)... you get T=4
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