Please help me! I am running out of time and I need to have this done!
Consider the line that passes through the point (3, -2) and has a slope of 2. Write the equation of this line using point-slope form.
Thank you so much!!
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So point slope form is y – y1 = m(x – x1)
where m is the slope and (x,y) are x and y
-2 – y1 = 2(3 – x1)
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Using the equation from the question above, rewrite this equation in slope-intercept form. Make sure to show all of your work.
So slope intercept form is y=mx+b
Where m is the slope, (x,y) are x and y, and b is this random constant.
If you substitute the slope in, you get
Substituting the x and y gets you
Solve the equation for the b
then plug-in the slope and b into the original slope intercept form
Thank you!! You are so good!
Can you hep me with just one more? Please!
Using the equation from just above, rewrite this equation in standard form. Make sure to show all of your work
So standard form is basically just shoving the x and y to one side of the equal sign and a constant on the other. From y=2x-8, you subtract the 2x to the other side to get
y-2x=-8. If you want to clean-up, 2x-y=8
Note that I'm not sure about standard form because it is seldom used after integrated algebra.
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