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So point slope form is y – y1 = m(x – x1) where m is the slope and (x,y) are x and y -2 – y1 = 2(3 – x1)
Thank you so much!! :3 ~ <3
Can you help me just a little more?
Using the equation from the question above, rewrite this equation in slope-intercept form. Make sure to show all of your work.
So slope intercept form is y=mx+b Where m is the slope, (x,y) are x and y, and b is this random constant. If you substitute the slope in, you get y=2x+b Substituting the x and y gets you -2=2(3)+b Solve the equation for the b b=-8 then plug-in the slope and b into the original slope intercept form y=2x-8
Thank you!! You are so good!
Can you hep me with just one more? Please!
Using the equation from just above, rewrite this equation in standard form. Make sure to show all of your work
So standard form is basically just shoving the x and y to one side of the equal sign and a constant on the other. From y=2x-8, you subtract the 2x to the other side to get y-2x=-8. If you want to clean-up, 2x-y=8
Note that I'm not sure about standard form because it is seldom used after integrated algebra.
That's okay! Don't worry!
Thank you soooooo very very much!!! You have saved me!! *yay!* I would give you right now a hug if I could! :D