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anonymous
 4 years ago
The triangle on the left has a perimeter of 14, the triangle on the right has a perimeter of 21. What are x and y? Show your steps. I could sit here and figure it out by guessing and substituting, but I'm assuming there is a formula to this, so help?
anonymous
 4 years ago
The triangle on the left has a perimeter of 14, the triangle on the right has a perimeter of 21. What are x and y? Show your steps. I could sit here and figure it out by guessing and substituting, but I'm assuming there is a formula to this, so help?

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jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1The left triangle has a perimeter of 14, so x+y+y = 14 x+2y = 14 solve for x to get x = 2y + 14

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1the triangle on the right has a perimeter of 21, so 3x+(5/4)y+(5/4)y = 21 12x+5y+5y = 84 ... multiply everything by the LCD 4 to clear out the fractions 12x+10y = 84 12(2y+14) + 10y = 84 ... plug in x = 2y + 14 Now solve for y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do I plug that in back at the same equation where I plugged in the other, then solve for x?

jim_thompson5910
 4 years ago
Best ResponseYou've already chosen the best response.1yes, you plug it into x = 2y + 14 to find x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Thank you so much I've been working at this for hours!!
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