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anonnnn

  • 3 years ago

The triangle on the left has a perimeter of 14, the triangle on the right has a perimeter of 21. What are x and y? Show your steps. I could sit here and figure it out by guessing and substituting, but I'm assuming there is a formula to this, so help?

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  1. anonnnn
    • 3 years ago
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  2. jim_thompson5910
    • 3 years ago
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    The left triangle has a perimeter of 14, so x+y+y = 14 x+2y = 14 solve for x to get x = -2y + 14

  3. jim_thompson5910
    • 3 years ago
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    the triangle on the right has a perimeter of 21, so 3x+(5/4)y+(5/4)y = 21 12x+5y+5y = 84 ... multiply everything by the LCD 4 to clear out the fractions 12x+10y = 84 12(-2y+14) + 10y = 84 ... plug in x = -2y + 14 Now solve for y

  4. anonnnn
    • 3 years ago
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    y = 6

  5. anonnnn
    • 3 years ago
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    Do I plug that in back at the same equation where I plugged in the other, then solve for x?

  6. jim_thompson5910
    • 3 years ago
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    yes, you plug it into x = -2y + 14 to find x

  7. anonnnn
    • 3 years ago
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    Thank you so much I've been working at this for hours!!

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