Quantcast

Got Homework?

Connect with other students for help. It's a free community.

  • across
    MIT Grad Student
    Online now
  • laura*
    Helped 1,000 students
    Online now
  • Hero
    College Math Guru
    Online now

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

monroe17

help? step by step Find dy/dx

  • one year ago
  • one year ago

  • This Question is Closed
  1. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    \[y=(12\sqrt[3]{x}-\frac{ 1 }{ 4x }+e^2)\]

    • one year ago
  2. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    I know I should rewrite it out.. 12*x^(1/3) but now I'm stuck..?

    • one year ago
  3. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    \[\sqrt[3]{x} = x^(\frac{ 1 }{ 3 }\] by the property, you subtract 1. So 1/3 - 1 = ? \[\frac{ 1 }{ 4x } = \frac{ 1 }{ 4 }x^{-1} \] and \[e^2 \] is just a constant.

    • one year ago
  4. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    \[x^{\frac{ 1 }{ 3 }}\]

    • one year ago
  5. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    okay, thanks.

    • one year ago
  6. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    \[y' = \frac{ 4 }{ x^{\frac{ 2 }{ 3 } }} - \frac{ 1 }{ 4x^2 }\]

    • one year ago
  7. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    so.. rewritten it's \[(12*x^{1/3}-\frac{ 1 }{ 4 }x^{-1}+e^2)\]

    • one year ago
  8. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    sorry, change the - to +.

    • one year ago
  9. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    ahhh i messed up on the original equation

    • one year ago
  10. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    \[(12\sqrt[3]{x}-\frac{ 1 }{ 4x }+e^2)^7\]

    • one year ago
  11. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    so it's chain rule right?

    • one year ago
  12. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    It's the same thing. now you apply chain rule.

    • one year ago
  13. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    \[7(4x^{\frac{ -2 }{ 3 }} + \frac{ 1 }{ 4x^2 })^6\]

    • one year ago
  14. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    mm.. the answer is different then that.

    • one year ago
  15. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    \[7(12\sqrt[3]{x}-\frac{ 1 }{ 4x }+e^2)^6(4x^{-2/3}+\frac{ 1 }{4 }x^{-2})\]

    • one year ago
  16. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    oh yeah, you multiply by the deriv again.

    • one year ago
  17. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    why do you multiply by the derivative?

    • one year ago
  18. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    oh nevermind haha

    • one year ago
  19. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    I got it.

    • one year ago
  20. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    I'm forgetting my simple rulessss! Ahhhh D;

    • one year ago
  21. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    chain rule states f'(g(x))*g'(x)

    • one year ago
  22. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    it's all good, i totally 4got chain rule for a moment. im rusty in my math

    • one year ago
  23. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    thanks so much though ;D

    • one year ago
  24. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    i remember the chain rule by ths let u equal some function within a function and y=\[f(u)\] so you have\[y=f(u)\] \[\frac{dy}{dx}=\frac{du}{dx}\frac{dy}{du}\] if you remember one party like du/dx or dy/du.... you'll know what you ned to cancel

    • one year ago
  25. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1355374308512:dw|

    • one year ago
  26. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    \[(x-2)^x\]

    • one year ago
  27. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    ^ I figured it out lol

    • one year ago
  28. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    chain rule?

    • one year ago
  29. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    i've never seen this lol.... suprisingly

    • one year ago
  30. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    i would've just chain ruled it

    • one year ago
  31. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    it's x-2^{x}

    • one year ago
  32. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    =1-2^{x}ln(2)

    • one year ago
  33. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    wat? Lol

    • one year ago
  34. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    nothing abb0t lol :)

    • one year ago
  35. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    is that an integration rule?

    • one year ago
  36. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    o gahd not the ln way of finding derivatives -.-

    • one year ago
  37. monroe17
    Best Response
    You've already chosen the best response.
    Medals 1

    lmao, ya --> ;/

    • one year ago
  38. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    wait for ODE for differentiation w/ integration.

    • one year ago
  39. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    what do you mean? i've taken Diff Eq

    • one year ago
  40. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    suprisingly i've gone all the way through math not seeing anything like that lol

    • one year ago
  41. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    or i did and it was a longg time ago

    • one year ago
  42. abb0t
    Best Response
    You've already chosen the best response.
    Medals 1

    for exact equations. also in PDE. chain rule.

    • one year ago
  43. Outkast3r09
    Best Response
    You've already chosen the best response.
    Medals 0

    exact dquations are simple, \[Ndy=Mdx\] or i might have the backwards i always seem to do it

    • one year ago
    • Attachments:

See more questions >>>

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.