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anonymous
 4 years ago
help? step by step
Find dy/dx
anonymous
 4 years ago
help? step by step Find dy/dx

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[y=(12\sqrt[3]{x}\frac{ 1 }{ 4x }+e^2)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know I should rewrite it out.. 12*x^(1/3) but now I'm stuck..?

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1\[\sqrt[3]{x} = x^(\frac{ 1 }{ 3 }\] by the property, you subtract 1. So 1/3  1 = ? \[\frac{ 1 }{ 4x } = \frac{ 1 }{ 4 }x^{1} \] and \[e^2 \] is just a constant.

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1\[y' = \frac{ 4 }{ x^{\frac{ 2 }{ 3 } }}  \frac{ 1 }{ 4x^2 }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so.. rewritten it's \[(12*x^{1/3}\frac{ 1 }{ 4 }x^{1}+e^2)\]

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1sorry, change the  to +.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ahhh i messed up on the original equation

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[(12\sqrt[3]{x}\frac{ 1 }{ 4x }+e^2)^7\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so it's chain rule right?

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1It's the same thing. now you apply chain rule.

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1\[7(4x^{\frac{ 2 }{ 3 }} + \frac{ 1 }{ 4x^2 })^6\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mm.. the answer is different then that.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[7(12\sqrt[3]{x}\frac{ 1 }{ 4x }+e^2)^6(4x^{2/3}+\frac{ 1 }{4 }x^{2})\]

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1oh yeah, you multiply by the deriv again.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why do you multiply by the derivative?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I'm forgetting my simple rulessss! Ahhhh D;

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1chain rule states f'(g(x))*g'(x)

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1it's all good, i totally 4got chain rule for a moment. im rusty in my math

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks so much though ;D

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i remember the chain rule by ths let u equal some function within a function and y=\[f(u)\] so you have\[y=f(u)\] \[\frac{dy}{dx}=\frac{du}{dx}\frac{dy}{du}\] if you remember one party like du/dx or dy/du.... you'll know what you ned to cancel

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1355374308512:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0^ I figured it out lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i've never seen this lol.... suprisingly

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i would've just chain ruled it

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that an integration rule?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0o gahd not the ln way of finding derivatives .

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1wait for ODE for differentiation w/ integration.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what do you mean? i've taken Diff Eq

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0suprisingly i've gone all the way through math not seeing anything like that lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or i did and it was a longg time ago

abb0t
 4 years ago
Best ResponseYou've already chosen the best response.1for exact equations. also in PDE. chain rule.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0exact dquations are simple, \[Ndy=Mdx\] or i might have the backwards i always seem to do it
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