anonymous
  • anonymous
Second derivative test to find the local extrema for the function?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
y = x^5-80x+100
anonymous
  • anonymous
i think it has to do with finding the f''(x)=0
anonymous
  • anonymous
I know that

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
y'(x) = 5x^4 -80
abb0t
  • abb0t
\[y' = 5x^4 -8\] \[y'' = 20x^3\]
anonymous
  • anonymous
y''(x) = 20x^3
abb0t
  • abb0t
set y'' = 0 and solve.
anonymous
  • anonymous
i got 0... so i wasn't sure if that's right
anonymous
  • anonymous
0 = 20x^3
abb0t
  • abb0t
Yes.
anonymous
  • anonymous
Okay thanks!
anonymous
  • anonymous
Oh i forgot, is it the local minimum (x=0)?
anonymous
  • anonymous
@abb0t
abb0t
  • abb0t
If the second derivative is zero then the critical point can be anything. Look @ the graph of ur function.
anonymous
  • anonymous
so it's just the local extrema is located at x=0
anonymous
  • anonymous
and if it's like... 3 and -3 as the local extrema. I don't know if it's a local max or min correct?
abb0t
  • abb0t
Only if it's zero. if < 0 = relative min if > 0 = relative max.
anonymous
  • anonymous
ohhhh ok! Thank you so much!

Looking for something else?

Not the answer you are looking for? Search for more explanations.