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timo86m
 2 years ago
Best ResponseYou've already chosen the best response.0i think it has to do with finding the f''(x)=0

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.1\[y' = 5x^4 8\] \[y'' = 20x^3\]

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0i got 0... so i wasn't sure if that's right

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0Oh i forgot, is it the local minimum (x=0)?

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.1If the second derivative is zero then the critical point can be anything. Look @ the graph of ur function.

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0so it's just the local extrema is located at x=0

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0and if it's like... 3 and 3 as the local extrema. I don't know if it's a local max or min correct?

abb0t
 2 years ago
Best ResponseYou've already chosen the best response.1Only if it's zero. if < 0 = relative min if > 0 = relative max.

swin2013
 2 years ago
Best ResponseYou've already chosen the best response.0ohhhh ok! Thank you so much!
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