Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
I'm on exam 4, question 5 b) and asked to setup an integral for arclength along a curve. I don't understand how the answer parametrizes the curve though without any initial conditions, here's the link: http://ocw.mit.edu/courses/mathematics/1801scsinglevariablecalculusfall2010/unit4techniquesofintegration/exam4/session86materialsforexam4/MIT18_01SCF10_exam4sol.pdf
 one year ago
 one year ago
I'm on exam 4, question 5 b) and asked to setup an integral for arclength along a curve. I don't understand how the answer parametrizes the curve though without any initial conditions, here's the link: http://ocw.mit.edu/courses/mathematics/1801scsinglevariablecalculusfall2010/unit4techniquesofintegration/exam4/session86materialsforexam4/MIT18_01SCF10_exam4sol.pdf
 one year ago
 one year ago

This Question is Closed

katzndogsBest ResponseYou've already chosen the best response.0
I instead found arclength in with respect to y since the x was given as a function of x but I m sure looking through my notes there whenever asked to parametrize initial conditions for t were provided. So any one out there with any idea could you be so kind to help. Thankyou!
 one year ago

katzndogsBest ResponseYou've already chosen the best response.0
*x was given as a function of y
 one year ago

beginnersmindBest ResponseYou've already chosen the best response.1
The initial condition is implicit in the choice t=y. We could have made the choice s=y1, which would have given x=s+1+(s+1)^3. We would need to change the limits of integration s=0 and s=3 (the values corresponding to y=1 and y=4). So we would integrate a slightly different function over different limits, leading to the same arc length. It's a matter of choice and if you try anything else you'll see how t=y leads to the simplest result.
 one year ago

katzndogsBest ResponseYou've already chosen the best response.0
I understand now! Thanks so much man for that great explanation! :)
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.