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burhan101Best ResponseYou've already chosen the best response.0
\[\[\huge 4\tan^2\sec^2x=0\]\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[4\tan^2 (x)\sec^2 (x)=0\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}\]\[\sec(\theta)=\frac{1}{\cos(\theta)}\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
•take the sec term to the other side of the equation, •substitute the above definitions into your equation, •multiply by the denominator •divide by 4 •take the sqrt of both sides , •take the inverse trig function to isolate x
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
tell me if you get stuck.
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
\[4\frac{ \sin^2x }{ \cos^2x }\frac{ 1 }{ \cos^2x }=0\]
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
multiply by cos^2
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
to subtract the two ??
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
(2sinx+1)(2sinx1) / cos^2x
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
how did that happen?
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
start again and follow the •'s
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
i'm going to be honest, im confused
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
by following the checlist this is what im getting sinxcosxsinx
 one year ago

HeroBest ResponseYou've already chosen the best response.2
May I suggest another approach?
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
my teacher has a completely different way im confuseeed
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
well im sure there are many different ways ,
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
1 + tan^2 x = sec^2 x tan^2 x = sec^2 x  1
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
i dont like that way as much as i like the way i have outlined , but that is opinion
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
4 ( sec^2 x  1)  sec^2 x = 0 4 sec^2 x  4  sec^2 x = 0 3 sec^2 x = 4 sec x = 2/ sqrt (3)
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
i am only allowed to have cos and sin in my answers
 one year ago

Yahoo!Best ResponseYou've already chosen the best response.0
Lol.....u shuld have Mentioned that in the question...)
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
Steps: 1. rearrange and isolate the unknown 2. move everything to one since, set equal to zero 3. use the zero principle 4. use inverse trig to find the angle 5. use CAST or ASTC to adjust answers @Yahoo! i know sorry ! :$
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
i just used my teachers method but everyone's explanations helped. thankyou :D
 one year ago

HeroBest ResponseYou've already chosen the best response.2
And what exactly was your teacher's method?
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
we're supposed to find what x can and cannot equal
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
so i just used basic trig and then looking at the unit circle i did elimination and listed the factors
 one year ago

HeroBest ResponseYou've already chosen the best response.2
That's not what you posted at the beginning
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
burhan101 0 Steps: 1. rearrange and isolate the unknown 2. move everything to one since, set equal to zero 3. use the zero principle 4. use inverse trig to find the angle 5. use CAST or ASTC to adjust answers
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
thats what i did, using the zero principle :
 one year ago

HeroBest ResponseYou've already chosen the best response.2
You mind showing some of those steps using the drawing button like I did?
 one year ago

burhan101Best ResponseYou've already chosen the best response.0
dw:1355393054138:dw
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
\[4\tan^2 (x)\sec^2 (x)=0\]\[4\tan^2 (x)=\sec^2 (x)\]\[4\left(\frac{\sin(x)}{\cos (x)}\right)^2 =\left(\frac1{\cos(x)}\right)^2\]\[4\frac{\sin^2(x)}{\cos^2 (x)} =\left(\frac1{\cos^2(x)}\right)\]\[4\sin^2(x)=\frac{\cos^2(x)}{\cos^2(x)}\]\[4\sin^2(x) =1\]\[\sin^2(x) =\frac14\]\[\sin(x)=\frac 12\]\[x=\arcsin\left(\frac12\right)=60°\]
 one year ago

HeroBest ResponseYou've already chosen the best response.2
@UnkleRhaukus, you ignore negative values?
 one year ago

UsukiDollBest ResponseYou've already chosen the best response.0
wow Hero that's just harsh, but...yeah..no comment
 one year ago

UsukiDollBest ResponseYou've already chosen the best response.0
I'm not saying it sucks or anything though
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.1
\[4\tan^2 (x)\sec^2 (x)=0\]\[4\tan^2 (x)(1+tan^2x)=0\]\[3\tan^2 (x)1=0\]\[tan^2x = \frac{1}{3}\]That shouldn't be difficult.
 one year ago

RolyPolyBest ResponseYou've already chosen the best response.1
Just use the identity \(1+tan^2x=sec^2x\)
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.1
@hero 0<x<2pi stated in question
 one year ago

HeroBest ResponseYou've already chosen the best response.2
I didn't see that second line. He posted it in pieces.
 one year ago
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