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burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0\[\[\huge 4\tan^2\sec^2x=0\]\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[4\tan^2 (x)\sec^2 (x)=0\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[\tan(\theta)=\frac{\sin(\theta)}{\cos(\theta)}\]\[\sec(\theta)=\frac{1}{\cos(\theta)}\]

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1•take the sec term to the other side of the equation, •substitute the above definitions into your equation, •multiply by the denominator •divide by 4 •take the sqrt of both sides , •take the inverse trig function to isolate x

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1tell me if you get stuck.

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0\[4\frac{ \sin^2x }{ \cos^2x }\frac{ 1 }{ \cos^2x }=0\]

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0to subtract the two ??

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0(2sinx+1)(2sinx1) / cos^2x

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1how did that happen?

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1start again and follow the •'s

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0i'm going to be honest, im confused

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0by following the checlist this is what im getting sinxcosxsinx

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2May I suggest another approach?

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0my teacher has a completely different way im confuseeed

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1well im sure there are many different ways ,

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.01 + tan^2 x = sec^2 x tan^2 x = sec^2 x  1

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1i dont like that way as much as i like the way i have outlined , but that is opinion

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.04 ( sec^2 x  1)  sec^2 x = 0 4 sec^2 x  4  sec^2 x = 0 3 sec^2 x = 4 sec x = 2/ sqrt (3)

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0i am only allowed to have cos and sin in my answers

Yahoo!
 2 years ago
Best ResponseYou've already chosen the best response.0Lol.....u shuld have Mentioned that in the question...)

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0Steps: 1. rearrange and isolate the unknown 2. move everything to one since, set equal to zero 3. use the zero principle 4. use inverse trig to find the angle 5. use CAST or ASTC to adjust answers @Yahoo! i know sorry ! :$

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0i just used my teachers method but everyone's explanations helped. thankyou :D

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2And what exactly was your teacher's method?

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0we're supposed to find what x can and cannot equal

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0so i just used basic trig and then looking at the unit circle i did elimination and listed the factors

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2That's not what you posted at the beginning

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0burhan101 0 Steps: 1. rearrange and isolate the unknown 2. move everything to one since, set equal to zero 3. use the zero principle 4. use inverse trig to find the angle 5. use CAST or ASTC to adjust answers

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0thats what i did, using the zero principle :

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2You mind showing some of those steps using the drawing button like I did?

burhan101
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1355393054138:dw

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1\[4\tan^2 (x)\sec^2 (x)=0\]\[4\tan^2 (x)=\sec^2 (x)\]\[4\left(\frac{\sin(x)}{\cos (x)}\right)^2 =\left(\frac1{\cos(x)}\right)^2\]\[4\frac{\sin^2(x)}{\cos^2 (x)} =\left(\frac1{\cos^2(x)}\right)\]\[4\sin^2(x)=\frac{\cos^2(x)}{\cos^2(x)}\]\[4\sin^2(x) =1\]\[\sin^2(x) =\frac14\]\[\sin(x)=\frac 12\]\[x=\arcsin\left(\frac12\right)=60°\]

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2@UnkleRhaukus, you ignore negative values?

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.0wow Hero that's just harsh, but...yeah..no comment

UsukiDoll
 2 years ago
Best ResponseYou've already chosen the best response.0I'm not saying it sucks or anything though

RolyPoly
 2 years ago
Best ResponseYou've already chosen the best response.1\[4\tan^2 (x)\sec^2 (x)=0\]\[4\tan^2 (x)(1+tan^2x)=0\]\[3\tan^2 (x)1=0\]\[tan^2x = \frac{1}{3}\]That shouldn't be difficult.

RolyPoly
 2 years ago
Best ResponseYou've already chosen the best response.1Just use the identity \(1+tan^2x=sec^2x\)

UnkleRhaukus
 2 years ago
Best ResponseYou've already chosen the best response.1@hero 0<x<2pi stated in question

Hero
 2 years ago
Best ResponseYou've already chosen the best response.2I didn't see that second line. He posted it in pieces.
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