A community for students.
Here's the question you clicked on:
 0 viewing
DLS
 2 years ago
siny=xsin(a+y)
dy/dx=?
DLS
 2 years ago
siny=xsin(a+y) dy/dx=?

This Question is Closed

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0I have a small doubt here..

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0is xsin(a+y) to be solved with product rule?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0dy/dx means you take the derivative of x... since sin(a+y) does not include any x in it... no, you don't use product rule. you treat sin(a+y) as a constant coefficient

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4ummm.... u need to use product rule...

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4because y is the function of x

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0What I want to ask is..if I had ysin(a+y) then I wuldve used chain rule?

lgbasallote
 2 years ago
Best ResponseYou've already chosen the best response.0you only use product rule when two facots include x for example xsin x < x and sinx both have x so you use product rule xsiny < siny doesn't have x so treat it as coefficient remember that @hartnn ?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4no, product again, because both are functions of x

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4sin y doesn't have x, right bu since y is the function of x....

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4d/dx sin y = cos y dy/dx

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0but even WFA treats it as 0

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4no...x sin(a+y) needs product rule.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4x cos(a+y) dy/dx + sin(a+y)

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4cos y dy/dx =x cos(a+y) dy/dx + sin(a+y) isolate dy/dx

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4your WFA http://www.wolframalpha.com/input/?i=siny%3Dxsin%28a%2By%29%2C++dy%2Fdx%3D%3F

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4it doesn't treat it as 0.

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0but still not clear why product rule..its used in product of 2 functions so x and sin(a+y) x is not a function,y is

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4x is a function of x x^1

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0every variable is afunction of itself then

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4you can say that. f(x) = x^n with n=1.

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0why didnt we use chain rule for sin(a+y)

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0sin is one function and y other right?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4cos (a+y) d/dx(a+y) =cos (a+y) (0+dy/dx)

DLS
 2 years ago
Best ResponseYou've already chosen the best response.0so I have to treat x&y both as function not variables but other variable like abcd as constants(0) ?

RolyPoly
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{d}{dx}xsin(a+y) \]\[=sin(a+y) \frac{d}{dx}(x) + x\frac{d}{dx}sin(a+y)\]\[=sin(a+y) + x[cos(a+y)\frac{d}{dx}(a+y)]\]\[=sin(a+y) + xcos(a+y)\frac{dy}{dx}\]

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.4here since y is the function of x, we treat it as different function. if a is function of x, then a is also function..... if a is independent of x, then a is constant.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.