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I have a small doubt here..

is xsin(a+y) to be solved with product rule?

:o?

ummm.... u need to use product rule...

I did..

because y is the function of x

What I want to ask is..if I had ysin(a+y) then I wuldve used chain rule?

no, product again, because both are functions of x

sin y doesn't have x, right
bu since y is the function of x....

d/dx sin y = cos y dy/dx

ive done that only

but even WFA treats it as 0

WFA ?

wolfaram :P ALPHA

spelling/*

no...x sin(a+y) needs product rule.

:/

x cos(a+y) dy/dx + sin(a+y)

cos y dy/dx =x cos(a+y) dy/dx + sin(a+y)
isolate dy/dx

your WFA
http://www.wolframalpha.com/input/?i=siny%3Dxsin%28a%2By%29%2C++dy%2Fdx%3D%3F

it doesn't treat it as 0.

oh nvm :o

x is a function of x
x^1

doesnt make any sense :S

every variable is afunction of itself then

you can say that.
f(x) = x^n with n=1.

why didnt we use chain rule for sin(a+y)

we actually did.

:o

sin is one function and y other right?

cos (a+y) d/dx(a+y)
=cos (a+y) (0+dy/dx)

yes.

so I have to treat x&y both as function not variables but other variable like abcd as constants(0) ?

when differentiating wrt x

clear!

:)