At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
We can use two methods 1-Substitution 2-Elimination.
no i don't really. Will you explain it to me?
Sure thing. lets take an example first.
Elimination method: When adding two equations, you basically add all parts of them. Say you had the equations: 4x + 5y = 14 -4x - 3y = -10 Adding them would give 2y = 4 4x + 5y = 14 + -4x - 3y = -10 2y = 4 As you can see, the 4x and -4x cancelled out, therefore eliminating the variable x, leaving an equation with only one variable (y), able to be solved. 2y = 4 y = 2 Now that you have a value for y, you must find one for x. To do this, just substitute the value for y into either original equation, and solve it for x 4x + 5(2) = 14 4x + 10 = 14 4x = 4 x = 1 Your solution for these two equations is (1, 2).
x + y = 4, and 2x + y = 7. First you work in one equation, solving for one variable in terms of another. Let's solve for y in terms of x in the first equation (you can do whichever variable in whichever equation you want, but you should experiment, and start recognizing which is the simplest one). x + y = 4 -x -x y = 4 - x Now this is where the substitution comes in. We substitute this value for y in the second equation. 2x + y = 7 2x + (4 - x) = 7 2x + 4 - x = 7 Combine like terms... x + 4 = 7 -4 -4 x = 3 Now you've solved for one variable, x, but you still need y. So...substitute your value for x into either equation and solve that linear equation to find y. x + y = 4 3 + y = 4 -3 -3 y = 1 The solution to this equation is x = 3, y = 1.
Its okay I think i get it (: thanks alot!!