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alwaysdancing18

  • 2 years ago

Classify the quadrilateral. Then, find the value(s) of the variable(s).

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  1. alwaysdancing18
    • 2 years ago
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    |dw:1355420237417:dw|

  2. mayankdevnani
    • 2 years ago
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    it's a KITE

  3. alwaysdancing18
    • 2 years ago
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    wow... not helpful

  4. mayankdevnani
    • 2 years ago
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    opposite sides are equal

  5. alwaysdancing18
    • 2 years ago
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    obviously

  6. mayankdevnani
    • 2 years ago
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    and find the values

  7. alwaysdancing18
    • 2 years ago
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    I dont know how to set the equation....

  8. AravindG
    • 2 years ago
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    opposit sides are not equal, it is the adjacent sides that are equal

  9. AravindG
    • 2 years ago
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    so 3x+6=6x+1

  10. alwaysdancing18
    • 2 years ago
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    well thats what I was thinking when he said that

  11. mayankdevnani
    • 2 years ago
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    opp. sides are equal so that 6x+1=3x+6 and 2y+6=4y-3 and then find values of x and y

  12. mayankdevnani
    • 2 years ago
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    yaaa correct!!!! @AravindG

  13. AravindG
    • 2 years ago
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    2y+6=4y-3

  14. AravindG
    • 2 years ago
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    solve for x and y and be happy :)

  15. alwaysdancing18
    • 2 years ago
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    I just look at the lines there. if they are the same then whala and this one question will not make me happy.... I have so many more

  16. mayankdevnani
    • 2 years ago
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    can you find the values? @alwaysdancing18

  17. alwaysdancing18
    • 2 years ago
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    y is not a whole number? I got 4 R1

  18. mayankdevnani
    • 2 years ago
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    |dw:1355410031710:dw|

  19. alwaysdancing18
    • 2 years ago
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    oh you wanted to do x first... ok.. umm 5/3

  20. mayankdevnani
    • 2 years ago
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    right

  21. mayankdevnani
    • 2 years ago
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    and same as second comment

  22. alwaysdancing18
    • 2 years ago
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    so y would be 9/2?

  23. mayankdevnani
    • 2 years ago
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    correct!!! you got it

  24. alwaysdancing18
    • 2 years ago
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    Thx... if you dont mind helping with two more?

  25. mayankdevnani
    • 2 years ago
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    sorry...g2g

  26. alwaysdancing18
    • 2 years ago
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    oh... thats ok Thanks anyway!!

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