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hba
 4 years ago
Integrate
hba
 4 years ago
Integrate

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hba
 4 years ago
Best ResponseYou've already chosen the best response.0\[\int\limits _{0}^{\infty} \lfloor x \rfloor e^{x} dx\]

Frostbite
 4 years ago
Best ResponseYou've already chosen the best response.0absolute value of x right?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I get 1, but i'll check again

Frostbite
 4 years ago
Best ResponseYou've already chosen the best response.0Hmm can't do the integral but the aproximation I do get to 1.

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1that initially seemed like floor value of x..... :P

Frostbite
 4 years ago
Best ResponseYou've already chosen the best response.0trid partial integration?

hba
 4 years ago
Best ResponseYou've already chosen the best response.0Yeah one more which i was doing was Integral (x^2/x^2+1) and i got x arctanx by trig sub.

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1thats correct....and can be done without substitution...

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.1if u can use this integral as standard int 1/(1+x^2) dx = arctan x +c

Frostbite
 4 years ago
Best ResponseYou've already chosen the best response.0btw forget what I said about partial integration... looks like geting no where.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0after IBP, i get the integral of: \[\large [e^{x}(x+1)]^\infty_0\] i made the leap that e^(x) tends to zero much faster than x+1 tends to infinity as x goes to infinity, but can't give a real justification right now

Frostbite
 4 years ago
Best ResponseYou've already chosen the best response.0Looks just about right Mathmuse. Seems like I made a bad choise when I did IBP.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0looks the same, wots 'sign(x)'?
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