A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
evaluate integral (sin t^2 )dt from 0 to infinite?
anonymous
 4 years ago
evaluate integral (sin t^2 )dt from 0 to infinite?

This Question is Open

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1355422740273:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you have to approximate the answer? Because its integrate indefinite is not an easy function...

across
 4 years ago
Best ResponseYou've already chosen the best response.0First find the antiderivative of \(\sin^2t\):\[\int\sin^2t\,dt=\frac t2\frac14\sin2t+c,\]then apply the limits:\[\left[\frac t2\frac14\sin2t\right]_0^\infty.\]However, since\[\lim_{t\to\infty}\sin 2t\]doesn't converge, the integral doesn't either.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No, he wrote \[\mathrm{ \int_{0}^\infty \sin(x^2)dx}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0http://www.wolframalpha.com/input/?i=+%5Cint_%7B0%7D%5E%5Cinfty+%5Csin%28x%5E2%29dx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\sum_{0}^{\infty} ((1)^k/(2k+1))*(x^2)^{2k+1}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thanks for all but i want the steps of solution
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.