Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
StupidGenius
Group Title
evaluate integral (sin t^2 )dt from 0 to infinite?
 one year ago
 one year ago
StupidGenius Group Title
evaluate integral (sin t^2 )dt from 0 to infinite?
 one year ago
 one year ago

This Question is Open

StupidGenius Group TitleBest ResponseYou've already chosen the best response.0
dw:1355422740273:dw
 one year ago

darthjavier Group TitleBest ResponseYou've already chosen the best response.0
Do you have to approximate the answer? Because its integrate indefinite is not an easy function...
 one year ago

across Group TitleBest ResponseYou've already chosen the best response.0
First find the antiderivative of \(\sin^2t\):\[\int\sin^2t\,dt=\frac t2\frac14\sin2t+c,\]then apply the limits:\[\left[\frac t2\frac14\sin2t\right]_0^\infty.\]However, since\[\lim_{t\to\infty}\sin 2t\]doesn't converge, the integral doesn't either.
 one year ago

darthjavier Group TitleBest ResponseYou've already chosen the best response.0
No, he wrote \[\mathrm{ \int_{0}^\infty \sin(x^2)dx}\]
 one year ago

darthjavier Group TitleBest ResponseYou've already chosen the best response.0
http://www.wolframalpha.com/input/?i=+%5Cint_%7B0%7D%5E%5Cinfty+%5Csin%28x%5E2%29dx
 one year ago

dorito Group TitleBest ResponseYou've already chosen the best response.0
\[\sum_{0}^{\infty} ((1)^k/(2k+1))*(x^2)^{2k+1}\]
 one year ago

StupidGenius Group TitleBest ResponseYou've already chosen the best response.0
thanks for all but i want the steps of solution
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.