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if x represents the sum of all the positive 3-digit nos that can be constructed using each of the distinct non zero digits a,b,c exactly once, wat is the largest integer by wic x must be divisible?

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no its 222
see it is clear for the sum of all 3-digited number is always divisible by 111
total no. of 3 digited nos as per ur question is 504 do u need the highest integer which divides the sum of all 504 numbers? or something else..

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if i am not wrong the sum of all 3 digited numbers is 279720 with each of the distinct non zero digits a,b,c exactly once it is divisible by integers greater than 222
?? r u there
how did u gt tis?? .. bit confused
see in any order the each digit 1 through 9 will appear as many as(8X7) times in the unit , tenth and hundredth place
now the sum of 1 through 9=45 hence required sum of all reqd + 3digited number is=45*56*(100+10+1)=279720
i hope it is clear to u or point where i am making mistake
see u might be rite but its jst not helping.... no offense but see its 3digit no so it shud be 9X8X7 Possibilities
yes u r correct that is total 504 numbers possible
k then
now each of the digits appear 504 /9 =56 times in each column
do u agree
now can u guess the sum total of each of the three columns
will it not be 56*(1+2+3....+9)=56*45=2520
am i correct...

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