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userneedinghelp

  • 2 years ago

I need help with the problem photographed at http://pbckt.com/pK.uB4qrd Thanks. Note tis not spam.

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  1. userneedinghelp
    • 2 years ago
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    @AriPotta

  2. AriPotta
    • 2 years ago
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    does that box say 225cm^3?

  3. userneedinghelp
    • 2 years ago
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    yes ma'am

  4. across
    • 2 years ago
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    Use the Pythagorean theorem.

  5. AriPotta
    • 2 years ago
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    mmk. so we know it's a square and it has an area of 225. how would we find the side length?

  6. userneedinghelp
    • 2 years ago
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    a2+b2=c2?

  7. userneedinghelp
    • 2 years ago
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    o side length is the square root of the area

  8. across
    • 2 years ago
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    Yes, now identify \(a\), \(b\) and \(c\) and solve for the unknown variable.

  9. userneedinghelp
    • 2 years ago
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    . ill solve n tell u what i got in five mins s, tnx

  10. userneedinghelp
    • 2 years ago
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    will you wait five mins plz?

  11. userneedinghelp
    • 2 years ago
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    u find the sq root of 17 and 225?

  12. AriPotta
    • 2 years ago
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    just find the square root of 225. 17 is the side length of that one square

  13. userneedinghelp
    • 2 years ago
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    oh. alright,.

  14. userneedinghelp
    • 2 years ago
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    tis 15

  15. userneedinghelp
    • 2 years ago
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    the sq root of 17 is about 8.5

  16. AriPotta
    • 2 years ago
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    you don't need the square root of 17

  17. userneedinghelp
    • 2 years ago
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    according to yahoo answers

  18. userneedinghelp
    • 2 years ago
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    oh mk

  19. userneedinghelp
    • 2 years ago
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    so 15+ 17 = c2?

  20. AriPotta
    • 2 years ago
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    a^2 + 15^2 = 17^2

  21. userneedinghelp
    • 2 years ago
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    wait. 17 is c. sorry

  22. userneedinghelp
    • 2 years ago
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    yea mk. let me solve one second.

  23. userneedinghelp
    • 2 years ago
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    i got 8

  24. AriPotta
    • 2 years ago
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    me too

  25. userneedinghelp
    • 2 years ago
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    cm^2

  26. AriPotta
    • 2 years ago
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    no, just 8cm

  27. userneedinghelp
    • 2 years ago
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    oh mk. one sec:)

  28. userneedinghelp
    • 2 years ago
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    thar we go:D

  29. userneedinghelp
    • 2 years ago
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    thank u

  30. userneedinghelp
    • 2 years ago
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    ill upload number 2 next. one sec

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