Quantcast

A community for students. Sign up today!

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

alfira

  • 2 years ago

help please!

  • This Question is Closed
  1. across
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    We're here to help.

  2. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    1 Attachment
  3. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    find the horzontal asymptotes

  4. across
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    All you have to do is determine the behavior of \(f\) as it approaches both \(-\infty\) and \(\infty\), i.e.,\[\lim_{x\to\infty}\frac{x^2+3}{\sqrt{x^2+1}}=?\]

  5. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    equal to 1 ?

  6. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    y=1?

  7. across
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    How did you get that?

  8. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    x^2 / X^2 +3/x^2

  9. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    everything divided by x^2

  10. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    because highest power in the function is x^2

  11. across
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Recall that\[\lim_{x\to\infty}\frac{x^2+3}{\sqrt{x^2+1}}=\lim_{x\to\infty}\frac{x^2}{\sqrt{x^2}}=\lim_{x\to\infty}\frac{x^2}{|x|}=\lim_{x\to\infty}x=\infty.\]

  12. across
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    So it has no horizontal asymptote as \(x\to\infty\). What about \(x\to-\infty\)?

  13. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    same thing ?

  14. across
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Right.

  15. alfira
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thanks `

  16. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Ask a Question
Find more explanations on OpenStudy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.