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anonymous
 3 years ago
Algebra 1, radicals help!
anonymous
 3 years ago
Algebra 1, radicals help!

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across
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{8q^{2}}{\sqrt{q^{17}}}=\frac{8q^{2}}{\sqrt{q^{14}q^{3}}}=\frac{8q^{2}}{\sqrt{q^{14}}q^{3/2}}=\frac{8\sqrt{q}}{q^7}.\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Oh geez, I posted the wrong question. @across

across
 3 years ago
Best ResponseYou've already chosen the best response.0First cross multiply and then solve for \(x\).

across
 3 years ago
Best ResponseYou've already chosen the best response.0That is,\[2x^2=10x+12.\]You may want to use the quadratic formula.

across
 3 years ago
Best ResponseYou've already chosen the best response.0That is, given\(ax^2+bx+c=0\), then\[x=\frac{b\pm\sqrt{b^24ac}}{2a}.\]
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