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KerenNicole

  • 3 years ago

Algebra 1, radicals help!

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  1. KerenNicole
    • 3 years ago
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  2. KerenNicole
    • 3 years ago
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    It's a correct?

  3. KerenNicole
    • 3 years ago
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    @jim_thompson5910

  4. across
    • 3 years ago
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    \[\frac{8q^{2}}{\sqrt{q^{17}}}=\frac{8q^{2}}{\sqrt{q^{14}q^{3}}}=\frac{8q^{2}}{\sqrt{q^{14}}q^{3/2}}=\frac{8\sqrt{q}}{q^7}.\]

  5. KerenNicole
    • 3 years ago
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    Oh geez, I posted the wrong question. @across

  6. KerenNicole
    • 3 years ago
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    There

  7. across
    • 3 years ago
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    First cross multiply and then solve for \(x\).

  8. across
    • 3 years ago
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    That is,\[2x^2=10x+12.\]You may want to use the quadratic formula.

  9. across
    • 3 years ago
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    That is, given\(ax^2+bx+c=0\), then\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}.\]

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