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KerenNicole Group TitleBest ResponseYou've already chosen the best response.0
It's a correct?
 one year ago

KerenNicole Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910
 one year ago

across Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{8q^{2}}{\sqrt{q^{17}}}=\frac{8q^{2}}{\sqrt{q^{14}q^{3}}}=\frac{8q^{2}}{\sqrt{q^{14}}q^{3/2}}=\frac{8\sqrt{q}}{q^7}.\]
 one year ago

KerenNicole Group TitleBest ResponseYou've already chosen the best response.0
Oh geez, I posted the wrong question. @across
 one year ago

across Group TitleBest ResponseYou've already chosen the best response.0
First cross multiply and then solve for \(x\).
 one year ago

across Group TitleBest ResponseYou've already chosen the best response.0
That is,\[2x^2=10x+12.\]You may want to use the quadratic formula.
 one year ago

across Group TitleBest ResponseYou've already chosen the best response.0
That is, given\(ax^2+bx+c=0\), then\[x=\frac{b\pm\sqrt{b^24ac}}{2a}.\]
 one year ago
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