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KerenNicole Group TitleBest ResponseYou've already chosen the best response.0
It's a correct?
 2 years ago

KerenNicole Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{8q^{2}}{\sqrt{q^{17}}}=\frac{8q^{2}}{\sqrt{q^{14}q^{3}}}=\frac{8q^{2}}{\sqrt{q^{14}}q^{3/2}}=\frac{8\sqrt{q}}{q^7}.\]
 2 years ago

KerenNicole Group TitleBest ResponseYou've already chosen the best response.0
Oh geez, I posted the wrong question. @across
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
First cross multiply and then solve for \(x\).
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
That is,\[2x^2=10x+12.\]You may want to use the quadratic formula.
 2 years ago

across Group TitleBest ResponseYou've already chosen the best response.0
That is, given\(ax^2+bx+c=0\), then\[x=\frac{b\pm\sqrt{b^24ac}}{2a}.\]
 2 years ago
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