KerenNicole
Algebra 1, radicals help!



This Question is Closed

KerenNicole
Best Response
You've already chosen the best response.
0

KerenNicole
Best Response
You've already chosen the best response.
0
It's a correct?

KerenNicole
Best Response
You've already chosen the best response.
0
@jim_thompson5910

across
Best Response
You've already chosen the best response.
0
\[\frac{8q^{2}}{\sqrt{q^{17}}}=\frac{8q^{2}}{\sqrt{q^{14}q^{3}}}=\frac{8q^{2}}{\sqrt{q^{14}}q^{3/2}}=\frac{8\sqrt{q}}{q^7}.\]

KerenNicole
Best Response
You've already chosen the best response.
0
Oh geez, I posted the wrong question. @across

KerenNicole
Best Response
You've already chosen the best response.
0
There

across
Best Response
You've already chosen the best response.
0
First cross multiply and then solve for \(x\).

across
Best Response
You've already chosen the best response.
0
That is,\[2x^2=10x+12.\]You may want to use the quadratic formula.

across
Best Response
You've already chosen the best response.
0
That is, given\(ax^2+bx+c=0\), then\[x=\frac{b\pm\sqrt{b^24ac}}{2a}.\]