anonymous
  • anonymous
I need help with the problem photographed at http://pbckt.com/pK.uBnvuh . The link is not spam.
Mathematics
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anonymous
  • anonymous
I need help with the problem photographed at http://pbckt.com/pK.uBnvuh . The link is not spam.
Mathematics
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous

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across
  • across
Hint: for a square, its area \(A\) in terms of its side length \(s\) is\[A=s^2.\]
ghazi
  • ghazi
you need to find the perimeter
anonymous
  • anonymous
okay
anonymous
  • anonymous
let me reread
ghazi
  • ghazi
and to find perimeter first find the side and then use 4*side
anonymous
  • anonymous
hmm. lemme try
ghazi
  • ghazi
:)
anonymous
  • anonymous
ive to find side length?
ghazi
  • ghazi
yes , you have been given area of the square and use the formula that across has mentioned
anonymous
  • anonymous
will do. let me give it a shot.:)
anonymous
  • anonymous
88^2?
anonymous
  • anonymous
no...wrong. srrY
anonymous
  • anonymous
would you please work it out for me? explain,i mean
ghazi
  • ghazi
\[A=s^2\]\[s= \sqrt{352}=18.76\] and then perimeter = 4*18.96= 75.04
anonymous
  • anonymous
oh. mk. let me look over that reply again
anonymous
  • anonymous
mk. i get it:)
anonymous
  • anonymous
my name is rachel. nice to meet u
anonymous
  • anonymous
*shakes hands with gazi*
anonymous
  • anonymous
and tnx:)
across
  • across
Jesus, there should be an option to unsubscribe from question notifications.
ghazi
  • ghazi
shaking hand to you too, but you have missed that meeting with real genius @across
ghazi
  • ghazi
you're right lol
anonymous
  • anonymous
i bow down to you,across
anonymous
  • anonymous
sorry...my replies must annoy u
across
  • across
n_n; I'm glad you're enjoying OS.
ghazi
  • ghazi
@across deserves it
anonymous
  • anonymous
oh, i am lol. ive been a user of this fine community for a long time
anonymous
  • anonymous
across deserves what? a medal?
ghazi
  • ghazi
@across deserves your bows , she is the real genius , go to her profile you will get to know lol
anonymous
  • anonymous
lol. :D
anonymous
  • anonymous
well, thank u both

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