## xKingx 2 years ago How would I simplify this?

1. xKingx

2. across

Hint:$\sqrt{6w^3}\sqrt{12w}=\sqrt{72w^4}.$

3. xKingx

It was actually supposed to be something like: 6^(3/2)w^(3/2) * 2sqrt3w. Any idea how'd they get that?

4. xKingx

5. across

I just gave you a hint. The "right" answer was obtained by decomposing everything into prime powers, like this:$\sqrt{6w^3}\sqrt{12w}=\sqrt{6w^3}\sqrt{2^2\cdot3w}=\sqrt{6w^3}2\sqrt{3w}.$I have no clue how you obtained $$(6w)^{3/2}$$ for the first term.

6. rodude

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