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across
 2 years ago
Best ResponseYou've already chosen the best response.1Hint:\[\sqrt{6w^3}\sqrt{12w}=\sqrt{72w^4}.\]

xKingx
 2 years ago
Best ResponseYou've already chosen the best response.0It was actually supposed to be something like: 6^(3/2)w^(3/2) * 2sqrt3w. Any idea how'd they get that?

xKingx
 2 years ago
Best ResponseYou've already chosen the best response.0Your answer is the same I got just for the record.

across
 2 years ago
Best ResponseYou've already chosen the best response.1I just gave you a hint. The "right" answer was obtained by decomposing everything into prime powers, like this:\[\sqrt{6w^3}\sqrt{12w}=\sqrt{6w^3}\sqrt{2^2\cdot3w}=\sqrt{6w^3}2\sqrt{3w}.\]I have no clue how you obtained \((6w)^{3/2}\) for the first term.
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