Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Compassionate
Group Title
Lets get a good thread going on here.
Post mathematical questions here, and we all help each other out by solving them.
 2 years ago
 2 years ago
Compassionate Group Title
Lets get a good thread going on here. Post mathematical questions here, and we all help each other out by solving them.
 2 years ago
 2 years ago

This Question is Closed

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
It's one big math solving orgy in this thread.
 2 years ago

bibby Group TitleBest ResponseYou've already chosen the best response.0
This isn't even a forum nignog
 2 years ago

skullpatrol Group TitleBest ResponseYou've already chosen the best response.0
Does 0.999... = 1? Let the orgy begin.
 2 years ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
No, because 0.999 will never exceed by 1 point.
 2 years ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
Bibby, don't ruin the potential of this thread.
 2 years ago

bibby Group TitleBest ResponseYou've already chosen the best response.0
They eventually converge
 2 years ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
If you try to derail my thread, I will steal your waifu
 2 years ago

bibby Group TitleBest ResponseYou've already chosen the best response.0
I don't even have a waifu. My question: is onesided infatuation real love?
 2 years ago

Aylin Group TitleBest ResponseYou've already chosen the best response.5
@skullpatrol .99999999... repeating is the same as 1. Proof: x=.9999999999 10x=9.999999999 10xx=9.999999999.99999999999 9x=9 x=1
 2 years ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
Bibby, of course it's real love. Don't you get butterflies in your stomach when your waifu comes to cheer you up? Also, pic related, Mai Waifu is drinking tea. Ayin, nope, your equation is nonsensical.
 2 years ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
That's not a valid proof.
 2 years ago

bibby Group TitleBest ResponseYou've already chosen the best response.0
live footage of my waifu
 2 years ago

skullpatrol Group TitleBest ResponseYou've already chosen the best response.0
http://en.wikipedia.org/wiki/0.999...
 2 years ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
I got one for you guys. 1/0 = n n x 0 = 1
 2 years ago

skullpatrol Group TitleBest ResponseYou've already chosen the best response.0
Your 2nd equation violates the multiplicative property of 0. How can 0 times any number be 1?
 2 years ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
Because every number is 0, n must be infinite.
 2 years ago

Aylin Group TitleBest ResponseYou've already chosen the best response.5
That's...not how vector fields work.
 2 years ago

skullpatrol Group TitleBest ResponseYou've already chosen the best response.0
Infinity is not a number. If it is give me its value?
 2 years ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
Mata, mata. A x B = C C/A = B C/B = A 10 x 0 = 0 0/10 = 0 0/0 = 10
 2 years ago

Aylin Group TitleBest ResponseYou've already chosen the best response.5
Incorrect. If you start with A x B = C, you can only say C/A=B if you exclude the possibility that A might be 0. Likewise with C/B=A.
 2 years ago

skullpatrol Group TitleBest ResponseYou've already chosen the best response.0
I can replace your 10 with "any number" to get 0/0 = "any number."
 2 years ago

skullpatrol Group TitleBest ResponseYou've already chosen the best response.0
10 x 0 = 0 or a*0 = 0 0/10 = 0 or 0/a = 0 0/0 = 10 or 0/0 = a where a = any number
 2 years ago

skullpatrol Group TitleBest ResponseYou've already chosen the best response.0
What happened to the party?
 2 years ago

Aylin Group TitleBest ResponseYou've already chosen the best response.5
How 'bout this: Prove that \[\sum_{n=1}^{\infty} \frac{ 1 }{ k }\]diverges.
 2 years ago

muntoo Group TitleBest ResponseYou've already chosen the best response.0
@Aylin assuming n=k, http://en.wikipedia.org/wiki/Harmonic_series_(mathematics)#Divergence If n is not equal to k, I give up. The problem is too difficult for me. Maybe some Wiles will come along and write a 300 page proof.
 2 years ago

muntoo Group TitleBest ResponseYou've already chosen the best response.0
Remove the summation ("simplify"): \[ \large \sum_{n=0}^{k}{2^k} \] Think you're so tough? Simplify: \[ \large \sum_{n=0}^{k}{3^k} \]
 2 years ago

Aylin Group TitleBest ResponseYou've already chosen the best response.5
Er... @muntoo the way you've written them the answers would just be \[k \times 2^{2}\]and\[k \times 3^{k}\]respectively.
 2 years ago

Compassionate Group TitleBest ResponseYou've already chosen the best response.0
Bump ~~
 2 years ago

muntoo Group TitleBest ResponseYou've already chosen the best response.0
@Aylin Whoops: \[\Large \sum_{n=0}^{k}{2^n}\]\[\Large \sum_{n=0}^{k}{3^n}\]
 2 years ago

Aylin Group TitleBest ResponseYou've already chosen the best response.5
@muntoo \[\sum_{n=0}^{k}2^{n}=1+2+4+8+16+32+...\frac{ 2^{k} }{ 4 }+\frac{ 2^{k} }{ 2 }+2^{k}\]\[=1+2(1+2+4+8+...+\frac{ 2^{k} }{ 8 }+\frac{ 2^{k} }{ 4 }+\frac{ 2^{k} }{ 2 })\]\[=2 \times 2^{k}(\frac{ 1 }{ 2 }+\frac{ 1 }{ 4 }+\frac{ 1 }{ 8 }+...+\frac{ 2 }{ 2^{k} }+\frac{ 1 }{ 2^{k} })+1\]\[=2 \times 2^{k} \times \sum_{n=1}^{k}\frac{ 1 }{ 2^{n} }+1=2 \times 2^{k} \times (12^{k})+1\]\[=2 \times 2^{k}2+1=2 \times 2^k1\] \[\sum_{n=0}^{k}3^{n}=1+3+9+27+81+...+\frac{ 3^{k} }{ 9 }+\frac{ 3^{k} }{ 3 }+3^{k}\]\[=3 \times 3^{k} \times (\frac{ 1 }{ 3 }+\frac{ 1 }{ 9 }+\frac{ 1 }{ 27 }+...+\frac{ 3 }{ 3^{k} }+\frac{ 1 }{ 3^{k} })+1\]\[=3 \times 3^{k} \times \sum_{n=1}^{k}\frac{ 1 }{ 3^{n}}+1\]\[=3 \times 3^{k} \times (\frac{ 1 }{ 2 }\frac{ 1 }{ 2 \times 3^{k} })+1\]\[=\frac{ 3 }{ 2 }3^{k}\frac{ 3 }{ 2 }=\frac{ 3 \times 3^{k} }{ 2 }\frac{ 1 }{ 2 }\]
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.