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Well the idea is to isolate y right? What would be your first step?
You have a cube root. How would you get rid of that?
For instance, if you have a square root you have to square to get rid of the square root.
So I would cube both sides?
Is my answer 2?
It didn't work. :/
the answer is 8! :D
Ohh wait. I am dumb.
3^3 is 27 >.< .
thanks for your help! I was having so much trouble
Yeah it's 8 :P .
could you help me with another?
Okay, square both sides again :) .
okay so now i have x+10=(x+10)^2
Can you expand the (x+10)^2 ?
okay I am a bit confused
what I am supposed to do
Okay so we have: |dw:1355462917095:dw|
okay I sort of see where this is going
You realize we have to foil this correct?
What did you get?
-10 and -9?
Very good! :) .
Algebra isn't that bad once you get the hang of it :) .
I have a algebra final tomorrow. I am pretty nervous.
Haha, you will be fine ^_^ .
I am working on this problem right now and I got 3 but it says it's wrong. √(6a-2)=16
not 16 I meant -4
So square both sides :) .
Keep the negative inside the brackets when you square, so it would be like (-4)^2 .
but wouldn't that be 16?
Yep :) .
A genral rule is when you square both sides and the negative it attached to a number, You put the negative in brackets and them square it.
Because when you square you are basically going -4 * -4 which his 16 ( negative * negative is +) .
Okay. Well I got the final answer to be 3. But it says that that is wrong. Why is that?
So when you square both sides, what did you get?
It's strange, that's absolutely correct.
That's what I thought. It's online hw. And it tells you when it's right or wrong.
nevermind it was does not exist
probably because it was a -4
No, that's not why.
It depends on the sign of the square root.
If it's a POSITIVE square root then yes, no solutions exist.
But if it's -√(6a-2) then it's 3.
Because when you take the square root of a function it's always in the form of ±√ f(x) . We need to know the proper sign.
That question was badly worded.
You can say that again!
Only if you are up for it!
Square both sides :P .
I found the answer
It's a procedure essentially :P .
What did you get?
does not exist
what about this one?
Square both sides :) .
We have: |dw:1355464812127:dw|
You square the WHOLE thing :) .
so what do i do now?
After squaring both sides?
Get all the y's on one side.
I think I am having trouble squaring them.
oh so I foil
You should get the same answer no matter what you use.
What did you do?
I am moving the y's
I think I am doing this wrong