francescazares2012
What would y be?
^3√(3y+3)=3



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Dido525
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Well the idea is to isolate y right? What would be your first step?

Dido525
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You have a cube root. How would you get rid of that?

Dido525
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For instance, if you have a square root you have to square to get rid of the square root.

Dido525
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@francescazares2012 : You there?


francescazares2012
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So I would cube both sides?

Dido525
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Yep!

francescazares2012
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Is my answer 2?

Dido525
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Good job!

francescazares2012
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It didn't work. :/

francescazares2012
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the answer is 8! :D

Dido525
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Ohh wait. I am dumb.

Dido525
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3^3 is 27 >.< .

francescazares2012
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thanks for your help! I was having so much trouble

Dido525
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Yeah it's 8 :P .

francescazares2012
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could you help me with another?

Dido525
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Sure.


Dido525
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Okay, square both sides again :) .

francescazares2012
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okay so now i have x+10=(x+10)^2

Dido525
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Can you expand the (x+10)^2 ?


Dido525
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dw:1355462739047:dw

francescazares2012
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okay I am a bit confused

Dido525
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With?

francescazares2012
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what I am supposed to do

Dido525
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Okay so we have:
dw:1355462917095:dw

Dido525
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dw:1355463044826:dw

francescazares2012
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okay I sort of see where this is going

Dido525
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You realize we have to foil this correct?

Dido525
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dw:1355463252789:dw


Dido525
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What did you get?


Dido525
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Very good! :) .


Dido525
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Algebra isn't that bad once you get the hang of it :) .

francescazares2012
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I have a algebra final tomorrow. I am pretty nervous.

Dido525
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Haha, you will be fine ^_^ .

francescazares2012
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I am working on this problem right now and I got 3 but it says it's wrong.
√(6a2)=16

francescazares2012
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not 16 I meant 4


Dido525
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So square both sides :) .

Dido525
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Keep the negative inside the brackets when you square, so it would be like (4)^2 .

francescazares2012
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but wouldn't that be 16?

Dido525
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Yep :) .

Dido525
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A genral rule is when you square both sides and the negative it attached to a number, You put the negative in brackets and them square it.

Dido525
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Because when you square you are basically going 4 * 4 which his 16 ( negative * negative is +) .

francescazares2012
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Okay. Well I got the final answer to be 3. But it says that that is wrong. Why is that?

Dido525
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So when you square both sides, what did you get?

Dido525
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It's strange, that's absolutely correct.

francescazares2012
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That's what I thought. It's online hw. And it tells you when it's right or wrong.

francescazares2012
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nevermind it was does not exist

francescazares2012
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probably because it was a 4

Dido525
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No, that's not why.

Dido525
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It depends on the sign of the square root.

Dido525
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If it's a POSITIVE square root then yes, no solutions exist.

Dido525
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But if it's √(6a2) then it's 3.

Dido525
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Because when you take the square root of a function it's always in the form of ±√ f(x) . We need to know the proper sign.

Dido525
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That question was badly worded.

francescazares2012
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You can say that again!

Dido525
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Anything else?

francescazares2012
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Only if you are up for it!


Dido525
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Square both sides :P .

francescazares2012
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I found the answer

Dido525
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It's a procedure essentially :P .

Dido525
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What did you get?

francescazares2012
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does not exist

Dido525
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Good job!


francescazares2012
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what about this one?

Dido525
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Square both sides :) .



Dido525
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No....

Dido525
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We have:
dw:1355464812127:dw

Dido525
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You square the WHOLE thing :) .


francescazares2012
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so what do i do now?

Dido525
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After squaring both sides?


Dido525
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Get all the y's on one side.

francescazares2012
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I think I am having trouble squaring them.

Dido525
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dw:1355465159249:dw


Dido525
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You should get the same answer no matter what you use.


Dido525
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What did you do?

francescazares2012
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I am moving the y's

francescazares2012
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I think I am doing this wrong