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francescazares2012

What would y be? ^3√(3y+3)=3

  • one year ago
  • one year ago

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  1. Dido525
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    Well the idea is to isolate y right? What would be your first step?

    • one year ago
  2. Dido525
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    You have a cube root. How would you get rid of that?

    • one year ago
  3. Dido525
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    For instance, if you have a square root you have to square to get rid of the square root.

    • one year ago
  4. Dido525
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    @francescazares2012 : You there?

    • one year ago
  5. francescazares2012
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    yes

    • one year ago
  6. francescazares2012
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    So I would cube both sides?

    • one year ago
  7. Dido525
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    Yep!

    • one year ago
  8. francescazares2012
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    Is my answer 2?

    • one year ago
  9. Dido525
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    Good job!

    • one year ago
  10. francescazares2012
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    It didn't work. :/

    • one year ago
  11. francescazares2012
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    the answer is 8! :D

    • one year ago
  12. Dido525
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    Ohh wait. I am dumb.

    • one year ago
  13. Dido525
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    3^3 is 27 >.< .

    • one year ago
  14. francescazares2012
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    thanks for your help! I was having so much trouble

    • one year ago
  15. Dido525
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    Yeah it's 8 :P .

    • one year ago
  16. francescazares2012
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    could you help me with another?

    • one year ago
  17. Dido525
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    Sure.

    • one year ago
  18. francescazares2012
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    √(x+10)=x+10

    • one year ago
  19. Dido525
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    Okay, square both sides again :) .

    • one year ago
  20. francescazares2012
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    okay so now i have x+10=(x+10)^2

    • one year ago
  21. Dido525
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    Can you expand the (x+10)^2 ?

    • one year ago
  22. francescazares2012
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    yes

    • one year ago
  23. Dido525
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    |dw:1355462739047:dw|

    • one year ago
  24. francescazares2012
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    okay I am a bit confused

    • one year ago
  25. Dido525
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    With?

    • one year ago
  26. francescazares2012
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    what I am supposed to do

    • one year ago
  27. Dido525
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    Okay so we have: |dw:1355462917095:dw|

    • one year ago
  28. Dido525
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    |dw:1355463044826:dw|

    • one year ago
  29. francescazares2012
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    okay I sort of see where this is going

    • one year ago
  30. Dido525
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    You realize we have to foil this correct?

    • one year ago
  31. Dido525
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    |dw:1355463252789:dw|

    • one year ago
  32. francescazares2012
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    okay

    • one year ago
  33. Dido525
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    What did you get?

    • one year ago
  34. francescazares2012
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    -10 and -9?

    • one year ago
  35. Dido525
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    Very good! :) .

    • one year ago
  36. francescazares2012
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    wow!

    • one year ago
  37. Dido525
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    Algebra isn't that bad once you get the hang of it :) .

    • one year ago
  38. francescazares2012
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    I have a algebra final tomorrow. I am pretty nervous.

    • one year ago
  39. Dido525
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    Haha, you will be fine ^_^ .

    • one year ago
  40. francescazares2012
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    I am working on this problem right now and I got 3 but it says it's wrong. √(6a-2)=16

    • one year ago
  41. francescazares2012
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    not 16 I meant -4

    • one year ago
  42. francescazares2012
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    so √(6a-2)=-4

    • one year ago
  43. Dido525
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    So square both sides :) .

    • one year ago
  44. Dido525
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    Keep the negative inside the brackets when you square, so it would be like (-4)^2 .

    • one year ago
  45. francescazares2012
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    but wouldn't that be 16?

    • one year ago
  46. Dido525
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    Yep :) .

    • one year ago
  47. Dido525
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    A genral rule is when you square both sides and the negative it attached to a number, You put the negative in brackets and them square it.

    • one year ago
  48. Dido525
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    Because when you square you are basically going -4 * -4 which his 16 ( negative * negative is +) .

    • one year ago
  49. francescazares2012
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    Okay. Well I got the final answer to be 3. But it says that that is wrong. Why is that?

    • one year ago
  50. Dido525
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    So when you square both sides, what did you get?

    • one year ago
  51. Dido525
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    It's strange, that's absolutely correct.

    • one year ago
  52. francescazares2012
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    That's what I thought. It's online hw. And it tells you when it's right or wrong.

    • one year ago
  53. francescazares2012
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    nevermind it was does not exist

    • one year ago
  54. francescazares2012
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    probably because it was a -4

    • one year ago
  55. Dido525
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    No, that's not why.

    • one year ago
  56. Dido525
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    It depends on the sign of the square root.

    • one year ago
  57. Dido525
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    If it's a POSITIVE square root then yes, no solutions exist.

    • one year ago
  58. Dido525
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    But if it's -√(6a-2) then it's 3.

    • one year ago
  59. Dido525
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    Because when you take the square root of a function it's always in the form of ±√ f(x) . We need to know the proper sign.

    • one year ago
  60. Dido525
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    That question was badly worded.

    • one year ago
  61. francescazares2012
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    You can say that again!

    • one year ago
  62. Dido525
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    Anything else?

    • one year ago
  63. francescazares2012
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    Only if you are up for it!

    • one year ago
  64. francescazares2012
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    √(x+6)=√(x)-6

    • one year ago
  65. Dido525
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    Square both sides :P .

    • one year ago
  66. francescazares2012
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    I found the answer

    • one year ago
  67. Dido525
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    It's a procedure essentially :P .

    • one year ago
  68. Dido525
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    What did you get?

    • one year ago
  69. francescazares2012
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    does not exist

    • one year ago
  70. Dido525
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    Good job!

    • one year ago
  71. francescazares2012
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    √(y+1)=√(y)+1

    • one year ago
  72. francescazares2012
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    what about this one?

    • one year ago
  73. Dido525
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    Square both sides :) .

    • one year ago
  74. francescazares2012
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    okay

    • one year ago
  75. francescazares2012
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    y+1=y+1?

    • one year ago
  76. Dido525
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    No....

    • one year ago
  77. Dido525
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    We have: |dw:1355464812127:dw|

    • one year ago
  78. Dido525
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    You square the WHOLE thing :) .

    • one year ago
  79. francescazares2012
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    oh okay

    • one year ago
  80. francescazares2012
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    so what do i do now?

    • one year ago
  81. Dido525
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    After squaring both sides?

    • one year ago
  82. francescazares2012
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    yes

    • one year ago
  83. Dido525
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    Get all the y's on one side.

    • one year ago
  84. francescazares2012
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    I think I am having trouble squaring them.

    • one year ago
  85. Dido525
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    |dw:1355465159249:dw|

    • one year ago
  86. francescazares2012
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    oh so I foil

    • one year ago
  87. Dido525
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    You should get the same answer no matter what you use.

    • one year ago
  88. francescazares2012
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    oh okay

    • one year ago
  89. Dido525
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    What did you do?

    • one year ago
  90. francescazares2012
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    I am moving the y's

    • one year ago
  91. francescazares2012
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    I think I am doing this wrong

    • one year ago
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