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 2 years ago
Which ordered pairs from the replacement set are solutions to the equation?
y = 2x + 9 ; Replacement Set {((1, 11), (0, 8), (1, 7), (2, 5)}
(1, 11)
(0, 8)
(1, 7)
(2, 5)
 2 years ago
Which ordered pairs from the replacement set are solutions to the equation? y = 2x + 9 ; Replacement Set {((1, 11), (0, 8), (1, 7), (2, 5)} (1, 11) (0, 8) (1, 7) (2, 5)

This Question is Closed

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.1Each ordered pair is of the form:\[(x _{1}, y _{1})\]You take each ordered pair and substitute like so:\[y _{1} = 2x _{1} + 9\]and see if it is true. You do this for each ordered pair, one at a time and test it. For your first ordered pair, the x1 = 1 and the y1 = 11. So, you can test the first one by substituting those values.

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.1So you ask yourself if: 11 = 2(1) + 9 is true or not.

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.1What is 2(1) ? Hint: that is 2 times 1

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.1To perform multiplication with negative signs, you first multiply the numbers and then if the number of "" signs is an even number, you have a positive result. Just saw your answer, so you probably already understand this. Good. So, continuing: 11 = 2(1) + 9 > 11 = 2 + 9 Yes, you already saw now that it works. Good job. Now just check the other 3 ordered pairs. Hint: only one doesn't work.

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.1So, this is making sense to you now?

Katlyn99
 2 years ago
Best ResponseYou've already chosen the best response.0yes it is I just needed a refresher

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.1I'm glad you're getting this. It's a great feeling when understanding comes. It's like a gift.

tcarroll010
 2 years ago
Best ResponseYou've already chosen the best response.1Good luck again and thx for the recognition!
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