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Which statement describes the translation of the graph of y=4(x-4)^2-2 from standard position? Moved up and to the right. Moved down and to the right. Moved down and to the left. Move up and to the left.

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If you plot this, then you'll answer this question yourself. :)
Okay but how will it be a translation??
okay i plotted the parabola where would the translation be? thats what I'm confused about..

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Other answers:

Translation simply means movement. In other words, what's the difference between \(y=x^2\) and \((x-4)^2-2\)? In this case, both horizontal and vertical translations are going on. How much does the graph move to the left/right? How much does it move up/down?
okay but from the vertex? What's the starting point?? I'm so confused...
It doesn't matter what the starting point is because the system is the two-dimensional euclidean plane; for simplicity, you could pick the vertex.
Well it moves and up and to the left and the starting point or point you're moving from would determine the answer??
Think of the graph as a whole, not a single point in it. How is \(y=x^2\) different from \(y=(x-4)^2-2\)? Here, I will draw it for you:|dw:1355525517186:dw|
It moves down and to the right?? thanks!!!

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