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abbie1

Which statement describes the translation of the graph of y=4(x-4)^2-2 from standard position? Moved up and to the right. Moved down and to the right. Moved down and to the left. Move up and to the left.

  • one year ago
  • one year ago

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  1. across
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    If you plot this, then you'll answer this question yourself. :)

    • one year ago
  2. abbie1
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    Okay but how will it be a translation??

    • one year ago
  3. abbie1
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    okay i plotted the parabola where would the translation be? thats what I'm confused about..

    • one year ago
  4. across
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    Translation simply means movement. In other words, what's the difference between \(y=x^2\) and \((x-4)^2-2\)? In this case, both horizontal and vertical translations are going on. How much does the graph move to the left/right? How much does it move up/down?

    • one year ago
  5. abbie1
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    okay but from the vertex? What's the starting point?? I'm so confused...

    • one year ago
  6. across
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    It doesn't matter what the starting point is because the system is the two-dimensional euclidean plane; for simplicity, you could pick the vertex.

    • one year ago
  7. abbie1
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    Well it moves and up and to the left and right..so the starting point or point you're moving from would determine the answer??

    • one year ago
  8. across
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    Think of the graph as a whole, not a single point in it. How is \(y=x^2\) different from \(y=(x-4)^2-2\)? Here, I will draw it for you:|dw:1355525517186:dw|

    • one year ago
  9. abbie1
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    It moves down and to the right?? thanks!!!

    • one year ago
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