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Write the missing statements and reasons of the proof.
Given:<A and <C are rt.<s; AB=CB
Prove:AD=CD
 one year ago
 one year ago
Write the missing statements and reasons of the proof. Given:<A and <C are rt.<s; AB=CB Prove:AD=CD
 one year ago
 one year ago

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sirm3dBest ResponseYou've already chosen the best response.1
what do you think is the reason for #1?
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
at #2. why are the triangles BAD and BCD right triangles?
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
? because they have right angles
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
that's exactly the definition of a right triangle. Reason #2: Definition of a Right Triangle
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
thnxs now how do i get number three
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
what do think is reason #3?
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
umm they are congruent
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
it is part of the given.
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
so #3 is part of a given
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
there are two given informations. (1) the right angles A and C, and (2) the congruent segments AB and CB. so you can use the reason "Given" twice.
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
oh okay i get it now statement 4 this is a little harder
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
the reflexive property is used when something is congruent/equal to itself, like \(\overline{PQ} \cong \overline{PQ}\) or \(\angle X \cong \angle X\) in the problem, what triangle part is used or common to the two triangles?
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
what is the common part, maybe an angle or a segment, of the two triangles?
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
right. \[\overline {BD} \cong \overline {BD}\]
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
5 is triangle BAD=BCD am i right
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
that goes into statement #5.
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
right it is. and for the reason?
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
I already have the reason done HL
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
the last line is what you were supposed to prove, \(\overline{AD}\cong \overline{CD}\)
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
thats what i thought thnxs so much for ur patience
 one year ago
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