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anonymous
 3 years ago
Write the missing statements and reasons of the proof.
Given:<A and <C are rt.<s; AB=CB
Prove:AD=CD
anonymous
 3 years ago
Write the missing statements and reasons of the proof. Given:<A and <C are rt.<s; AB=CB Prove:AD=CD

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355528472985:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355529709485:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what do you think is the reason for #1?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0at #2. why are the triangles BAD and BCD right triangles?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0? because they have right angles

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that's exactly the definition of a right triangle. Reason #2: Definition of a Right Triangle

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thnxs now how do i get number three

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what do think is reason #3?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0umm they are congruent

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is part of the given.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so #3 is part of a given

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0there are two given informations. (1) the right angles A and C, and (2) the congruent segments AB and CB. so you can use the reason "Given" twice.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh okay i get it now statement 4 this is a little harder

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the reflexive property is used when something is congruent/equal to itself, like \(\overline{PQ} \cong \overline{PQ}\) or \(\angle X \cong \angle X\) in the problem, what triangle part is used or common to the two triangles?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what is the common part, maybe an angle or a segment, of the two triangles?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355534984211:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right. \[\overline {BD} \cong \overline {BD}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.05 is triangle BAD=BCD am i right

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that goes into statement #5.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0right it is. and for the reason?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I already have the reason done HL

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0how about statement 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the last line is what you were supposed to prove, \(\overline{AD}\cong \overline{CD}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thats what i thought thnxs so much for ur patience
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