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ze4life

  • 2 years ago

Write the missing statements and reasons of the proof. Given:<A and <C are rt.<s; AB=CB Prove:AD=CD

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  1. ze4life
    • 2 years ago
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    |dw:1355528472985:dw|

  2. ze4life
    • 2 years ago
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    |dw:1355529709485:dw|

  3. sirm3d
    • 2 years ago
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    what do you think is the reason for #1?

  4. ze4life
    • 2 years ago
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    Given

  5. sirm3d
    • 2 years ago
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    at #2. why are the triangles BAD and BCD right triangles?

  6. ze4life
    • 2 years ago
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    ? because they have right angles

  7. ze4life
    • 2 years ago
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    90 degrees

  8. sirm3d
    • 2 years ago
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    that's exactly the definition of a right triangle. Reason #2: Definition of a Right Triangle

  9. ze4life
    • 2 years ago
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    thnxs now how do i get number three

  10. sirm3d
    • 2 years ago
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    what do think is reason #3?

  11. ze4life
    • 2 years ago
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    umm they are congruent

  12. ze4life
    • 2 years ago
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    ?

  13. sirm3d
    • 2 years ago
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    it is part of the given.

  14. ze4life
    • 2 years ago
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    so #3 is part of a given

  15. sirm3d
    • 2 years ago
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    Reason #3: Given

  16. sirm3d
    • 2 years ago
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    there are two given informations. (1) the right angles A and C, and (2) the congruent segments AB and CB. so you can use the reason "Given" twice.

  17. ze4life
    • 2 years ago
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    oh okay i get it now statement 4 this is a little harder

  18. ze4life
    • 2 years ago
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    ? :-(

  19. ze4life
    • 2 years ago
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    help plz

  20. sirm3d
    • 2 years ago
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    the reflexive property is used when something is congruent/equal to itself, like \(\overline{PQ} \cong \overline{PQ}\) or \(\angle X \cong \angle X\) in the problem, what triangle part is used or common to the two triangles?

  21. ze4life
    • 2 years ago
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    Triangle BCD?

  22. sirm3d
    • 2 years ago
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    what is the common part, maybe an angle or a segment, of the two triangles?

  23. sirm3d
    • 2 years ago
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    |dw:1355534984211:dw|

  24. ze4life
    • 2 years ago
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    BD

  25. ze4life
    • 2 years ago
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    segment BD

  26. sirm3d
    • 2 years ago
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    right. \[\overline {BD} \cong \overline {BD}\]

  27. ze4life
    • 2 years ago
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    5 is triangle BAD=BCD am i right

  28. sirm3d
    • 2 years ago
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    that goes into statement #5.

  29. sirm3d
    • 2 years ago
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    right it is. and for the reason?

  30. ze4life
    • 2 years ago
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    I already have the reason done HL

  31. ze4life
    • 2 years ago
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    how about statement 6

  32. sirm3d
    • 2 years ago
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    the last line is what you were supposed to prove, \(\overline{AD}\cong \overline{CD}\)

  33. ze4life
    • 2 years ago
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    thats what i thought thnxs so much for ur patience

  34. sirm3d
    • 2 years ago
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    YW

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