anonymous
  • anonymous
x^2/9 - (y-1)^2/16 = 1 name the vertices, and foci
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
let me revise it
anonymous
  • anonymous
ok thank you :)
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
a=9 b=16 As centre is (0,1) c^2=a^2+b^2 then c=+5and -5 as hyperbola is along x-axis so, vertices are (0+5,1) and(0-5,1) i.e. (5,1),(-5,1)

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anonymous
  • anonymous
is (0,1) the focii?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
no it is centre
anonymous
  • anonymous
What is the foci?
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
(5,1) and (-5,1) are focci i mistakenly wrote it as vertices
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
now i vertices are
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
(9,1),(-9,1)
sirm3d
  • sirm3d
@Muhammad_Nauman_Umair \(a^2=9\), not \(a=9\)
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
oh :( i need to go to sleep i m again mistaken @sirm3d u r write a should b 3 and b should be 4
Muhammad_Nauman_Umair
  • Muhammad_Nauman_Umair
right not write again mistaken @sirm3d

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