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Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
let me revise it
 one year ago

RenaAsf Group TitleBest ResponseYou've already chosen the best response.0
ok thank you :)
 one year ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
a=9 b=16 As centre is (0,1) c^2=a^2+b^2 then c=+5and 5 as hyperbola is along xaxis so, vertices are (0+5,1) and(05,1) i.e. (5,1),(5,1)
 one year ago

RenaAsf Group TitleBest ResponseYou've already chosen the best response.0
is (0,1) the focii?
 one year ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
no it is centre
 one year ago

RenaAsf Group TitleBest ResponseYou've already chosen the best response.0
What is the foci?
 one year ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
(5,1) and (5,1) are focci i mistakenly wrote it as vertices
 one year ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
now i vertices are
 one year ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
(9,1),(9,1)
 one year ago

sirm3d Group TitleBest ResponseYou've already chosen the best response.1
@Muhammad_Nauman_Umair \(a^2=9\), not \(a=9\)
 one year ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
oh :( i need to go to sleep i m again mistaken @sirm3d u r write a should b 3 and b should be 4
 one year ago

Muhammad_Nauman_Umair Group TitleBest ResponseYou've already chosen the best response.1
right not write again mistaken @sirm3d
 one year ago
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