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consider triangle DEF and triangle JKL,with DE=JK,EF=KL,and<EDF= KJL. Two sides and a nonincluded angle of one triangle are congruent to two sides and a nonincluded angle of the other triangle.From your solution to part A,is it correct to conclude that triangle DEF must be congruent to triangle JKL?answer yes or no and explain your answer using complete sentences.
 one year ago
 one year ago
consider triangle DEF and triangle JKL,with DE=JK,EF=KL,and<EDF= KJL. Two sides and a nonincluded angle of one triangle are congruent to two sides and a nonincluded angle of the other triangle.From your solution to part A,is it correct to conclude that triangle DEF must be congruent to triangle JKL?answer yes or no and explain your answer using complete sentences.
 one year ago
 one year ago

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ze4lifeBest ResponseYou've already chosen the best response.0
can u explain the question because i cant understand
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
Given two pairs of congruent segments and a pair of congruent angles opposite a pair of congruent segments.dw:1355538753912:dw can you conclude that the two sides are congruent?
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
can you conclude that the two TRIANGLES are congruent?
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
yes because if two angles of a triangle are congruent,then the sides opposite those angles are congruent
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
yesdw:1355539566118:dw
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
i'll think first of how to say it correctly, coz im not good with words.
 one year ago

ze4lifeBest ResponseYou've already chosen the best response.0
take ur time its alright
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
Let's begin with an isosceles triangle, and extending the base to one side.dw:1355539972915:dw
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
at the vertex, draw a segment to the extension of the base dw:1355540028031:dw
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
two triangles are formed satisfying the conditionsdw:1355540083358:dwdw:1355540128449:dw
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
you can construct your own explanation following the steps with illustration given above.
 one year ago
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