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TomLikesPhysicsBest ResponseYou've already chosen the best response.0
The function can be seen on the picture. I should show that y(0)=0 but I stuck at the step you see on the picture. It seems possible at that step that y(0)=0 is a solution but there still might be others too.
 one year ago

phiBest ResponseYou've already chosen the best response.0
without knowing what y(x) looks like, the best we can say is the equation is true for y(0)=0
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.1
I can follow all of your steps. The last one is: \[y(0)=\ln (1y(0))\]Now consider this: there are three possibilities for y(0): 1. y(0)=0 2. y(0)>0 3. y(0)<0 Can you see where this leads to?
 one year ago

ZeHanzBest ResponseYou've already chosen the best response.1
Suppose y(0) = 0. Because ln(10)=ln(1)=0, this works. What about other values instead of 0? Why wouldn't that be possible?
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
Ah, I see. All the other possibilities are ruled out because otherwise the last equation would make no sense.
 one year ago

TomLikesPhysicsBest ResponseYou've already chosen the best response.0
Thank you ZeHanz for your help.
 one year ago
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