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TomLikesPhysics
 2 years ago
Best ResponseYou've already chosen the best response.0The function can be seen on the picture. I should show that y(0)=0 but I stuck at the step you see on the picture. It seems possible at that step that y(0)=0 is a solution but there still might be others too.

phi
 2 years ago
Best ResponseYou've already chosen the best response.0without knowing what y(x) looks like, the best we can say is the equation is true for y(0)=0

ZeHanz
 2 years ago
Best ResponseYou've already chosen the best response.1I can follow all of your steps. The last one is: \[y(0)=\ln (1y(0))\]Now consider this: there are three possibilities for y(0): 1. y(0)=0 2. y(0)>0 3. y(0)<0 Can you see where this leads to?

ZeHanz
 2 years ago
Best ResponseYou've already chosen the best response.1Suppose y(0) = 0. Because ln(10)=ln(1)=0, this works. What about other values instead of 0? Why wouldn't that be possible?

TomLikesPhysics
 2 years ago
Best ResponseYou've already chosen the best response.0Ah, I see. All the other possibilities are ruled out because otherwise the last equation would make no sense.

TomLikesPhysics
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you ZeHanz for your help.
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