anonymous
  • anonymous
EMERGENCY PLEASE HELPPPPPPPPPPPPP!!!! :[ ... Will FAN and GIVE MEDAL !!! DESPERATE I know the answer to the first one is 6w^2√2 i just dont know how to show my work A.√(6w^(3)) √(12w) 4. The graph of f (x ) is show below ( cant get a photo but it looks like a normal graph with a 'w' to the left side on the graph) a. On this coordinate plane draw the graph of 1f (x )  . (1 pt) b. Is f (x ) a function? (1pt) c. Is 1f (x )  a function? (1 pt)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Can you please just type out the exact wording of the problem? 'm having a hard time understanding what exactly you're looking for.
ZeHanz
  • ZeHanz
Thank you for becoming my fan, but I really do not understand what the formula 6w^2√2 is supposed to mean...
anonymous
  • anonymous
1. Simplify each expression. Show all work, step-by-step. (3 pts each) a. √6w^3 times √12w

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More answers

ZeHanz
  • ZeHanz
Is it:\[\sqrt{6w^3}*\sqrt{12w}\]
anonymous
  • anonymous
yes :]
anonymous
  • anonymous
Simplified: 6 sqrt(2) w^2 (Picture attached with how it looks.)
anonymous
  • anonymous
ZeHanz
  • ZeHanz
In that case I would write\[\sqrt{72w^4}=\sqrt{36w^4}\sqrt{2}=6w^2\sqrt{2}\](assuming w>=0)
anonymous
  • anonymous
thank you so much you were both a great help !
ZeHanz
  • ZeHanz
As you can see, if you compare pathosdebaters' answer and mine, there are two ways to write the answer!
anonymous
  • anonymous
Yeah, both ways work since you can arrange multiplicative devices around with the same results.
anonymous
  • anonymous
awesome ! thanks so much now i just gotta figure out the last one lol im horrible with graphs
anonymous
  • anonymous
WHat's the exact wording of the problem?
anonymous
  • anonymous
4. The graph of f (x ) is show below a. On this coordinate plane draw the graph of 1f (x )  . (1 pt) b. Is f (x ) a function? (1pt) c. Is 1f (x )  a function? (1 pt)
anonymous
  • anonymous
|dw:1355608353124:dw|
anonymous
  • anonymous
thats a horrible drawing i did of the graph im looking at for number 4
anonymous
  • anonymous
pathosdebater still there ?

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