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1/x^2 + 1/x =6 solve for x

Mathematics
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make the left side into 1 equation.
multiply both sides by\(x^2\) and solve the resulting quadratic equation.
\[x^2/ x^2 + x^2/x^2 = 6x^2\]

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Other answers:

2x^2 = 6x^2
the denominator of your second term above is wrong
you should get:\[x^2/ x^2 + x^2/x = 6x^2\]
next - simplify each term
but dont they need to have the same denominator to add
what does \(x^2/x^2\) equal?
1
correct - now simplify the next term
1+ x= 6x^2
thats right - now re-arrange this into a standard form, i.e into the form \(ax^2+bx+c=0\) and then solve
so I did quadratic equation and go -1 plus or minus radical 25 all over -12
doesn't look right - can you please show your steps so that I can help spot where you may have made a mistake?
k, u said put it into the standard form so I started from 1 + x = 6x^2 -6x^2 + x+1 = 0 a= -6, b= 1, c= 1 \[-1\pm \sqrt{1^{2}-4(-6)(1) \over 2(-6)}\]
then got -1 plus or minus radical 25 all over -12
oh - sorry - I misread
you are right - and you know what \(\sqrt{25}\) equals?
the formula you used doesn't look quite right, it should be:\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
the WHOLE thing should be divided by 2a
so you should have got:\[\frac{-1\pm \sqrt{1^{2}-4(-6)(1)}}{2(-6)}\]
o ok so um x = 1/-3 and x = 1/2
perfect!
ya I ment to put all over 2a but I was trying to make it come out nice and pretty in the equation thing but it took lng
although you should write it as: x=-1/3 or 1/2
you don't usually put the minus sign in the denominator
wow these are so frustrating I was literally about to give up and go home, im in a library trying to study and there are all these other students basically hanging out and talking and there are no available tutors
also note that you should use the word "or" rather than "and" here. i.e. x = -1/3 or 1/2 instead of x = -1/3 and 1/2 because x canot equal both values at the same time
ok ill do that
thanks a lot you gave me a little hope to keep pushing a little more
great - and keep persevering - you'll get the hang of these very soon I'm sure :)
yw :)

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