anonymous
  • anonymous
1/x^2 + 1/x =6 solve for x
Mathematics
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anonymous
  • anonymous
1/x^2 + 1/x =6 solve for x
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
make the left side into 1 equation.
asnaseer
  • asnaseer
multiply both sides by\(x^2\) and solve the resulting quadratic equation.
anonymous
  • anonymous
\[x^2/ x^2 + x^2/x^2 = 6x^2\]

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anonymous
  • anonymous
2x^2 = 6x^2
asnaseer
  • asnaseer
the denominator of your second term above is wrong
asnaseer
  • asnaseer
you should get:\[x^2/ x^2 + x^2/x = 6x^2\]
asnaseer
  • asnaseer
next - simplify each term
anonymous
  • anonymous
but dont they need to have the same denominator to add
asnaseer
  • asnaseer
what does \(x^2/x^2\) equal?
anonymous
  • anonymous
1
asnaseer
  • asnaseer
correct - now simplify the next term
anonymous
  • anonymous
1+ x= 6x^2
asnaseer
  • asnaseer
thats right - now re-arrange this into a standard form, i.e into the form \(ax^2+bx+c=0\) and then solve
anonymous
  • anonymous
so I did quadratic equation and go -1 plus or minus radical 25 all over -12
asnaseer
  • asnaseer
doesn't look right - can you please show your steps so that I can help spot where you may have made a mistake?
anonymous
  • anonymous
k, u said put it into the standard form so I started from 1 + x = 6x^2 -6x^2 + x+1 = 0 a= -6, b= 1, c= 1 \[-1\pm \sqrt{1^{2}-4(-6)(1) \over 2(-6)}\]
anonymous
  • anonymous
then got -1 plus or minus radical 25 all over -12
asnaseer
  • asnaseer
oh - sorry - I misread
asnaseer
  • asnaseer
you are right - and you know what \(\sqrt{25}\) equals?
asnaseer
  • asnaseer
the formula you used doesn't look quite right, it should be:\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
asnaseer
  • asnaseer
the WHOLE thing should be divided by 2a
asnaseer
  • asnaseer
so you should have got:\[\frac{-1\pm \sqrt{1^{2}-4(-6)(1)}}{2(-6)}\]
anonymous
  • anonymous
o ok so um x = 1/-3 and x = 1/2
asnaseer
  • asnaseer
perfect!
anonymous
  • anonymous
ya I ment to put all over 2a but I was trying to make it come out nice and pretty in the equation thing but it took lng
asnaseer
  • asnaseer
although you should write it as: x=-1/3 or 1/2
asnaseer
  • asnaseer
you don't usually put the minus sign in the denominator
anonymous
  • anonymous
wow these are so frustrating I was literally about to give up and go home, im in a library trying to study and there are all these other students basically hanging out and talking and there are no available tutors
asnaseer
  • asnaseer
also note that you should use the word "or" rather than "and" here. i.e. x = -1/3 or 1/2 instead of x = -1/3 and 1/2 because x canot equal both values at the same time
anonymous
  • anonymous
ok ill do that
anonymous
  • anonymous
thanks a lot you gave me a little hope to keep pushing a little more
asnaseer
  • asnaseer
great - and keep persevering - you'll get the hang of these very soon I'm sure :)
asnaseer
  • asnaseer
yw :)

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