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make the left side into 1 equation.

multiply both sides by\(x^2\) and solve the resulting quadratic equation.

\[x^2/ x^2 + x^2/x^2 = 6x^2\]

2x^2 = 6x^2

the denominator of your second term above is wrong

you should get:\[x^2/ x^2 + x^2/x = 6x^2\]

next - simplify each term

but dont they need to have the same denominator to add

what does \(x^2/x^2\) equal?

correct - now simplify the next term

1+ x= 6x^2

so I did quadratic equation and go -1 plus or minus radical 25 all over -12

then got -1 plus or minus radical 25 all over -12

oh - sorry - I misread

you are right - and you know what \(\sqrt{25}\) equals?

the formula you used doesn't look quite right, it should be:\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

the WHOLE thing should be divided by 2a

so you should have got:\[\frac{-1\pm \sqrt{1^{2}-4(-6)(1)}}{2(-6)}\]

o ok so um x = 1/-3 and x = 1/2

perfect!

although you should write it as:
x=-1/3 or 1/2

you don't usually put the minus sign in the denominator

ok ill do that

thanks a lot you gave me a little hope to keep pushing a little more

great - and keep persevering - you'll get the hang of these very soon I'm sure :)

yw :)