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petewe Group TitleBest ResponseYou've already chosen the best response.0
make the left side into 1 equation.
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
multiply both sides by\(x^2\) and solve the resulting quadratic equation.
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
\[x^2/ x^2 + x^2/x^2 = 6x^2\]
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
the denominator of your second term above is wrong
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
you should get:\[x^2/ x^2 + x^2/x = 6x^2\]
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
next  simplify each term
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
but dont they need to have the same denominator to add
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
what does \(x^2/x^2\) equal?
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
correct  now simplify the next term
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
thats right  now rearrange this into a standard form, i.e into the form \(ax^2+bx+c=0\) and then solve
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
so I did quadratic equation and go 1 plus or minus radical 25 all over 12
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
doesn't look right  can you please show your steps so that I can help spot where you may have made a mistake?
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
k, u said put it into the standard form so I started from 1 + x = 6x^2 6x^2 + x+1 = 0 a= 6, b= 1, c= 1 \[1\pm \sqrt{1^{2}4(6)(1) \over 2(6)}\]
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
then got 1 plus or minus radical 25 all over 12
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
oh  sorry  I misread
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
you are right  and you know what \(\sqrt{25}\) equals?
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
the formula you used doesn't look quite right, it should be:\[x=\frac{b\pm\sqrt{b^24ac}}{2a}\]
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
the WHOLE thing should be divided by 2a
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
so you should have got:\[\frac{1\pm \sqrt{1^{2}4(6)(1)}}{2(6)}\]
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
o ok so um x = 1/3 and x = 1/2
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
ya I ment to put all over 2a but I was trying to make it come out nice and pretty in the equation thing but it took lng
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
although you should write it as: x=1/3 or 1/2
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
you don't usually put the minus sign in the denominator
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
wow these are so frustrating I was literally about to give up and go home, im in a library trying to study and there are all these other students basically hanging out and talking and there are no available tutors
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
also note that you should use the word "or" rather than "and" here. i.e. x = 1/3 or 1/2 instead of x = 1/3 and 1/2 because x canot equal both values at the same time
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
ok ill do that
 one year ago

P>Q Group TitleBest ResponseYou've already chosen the best response.1
thanks a lot you gave me a little hope to keep pushing a little more
 one year ago

asnaseer Group TitleBest ResponseYou've already chosen the best response.0
great  and keep persevering  you'll get the hang of these very soon I'm sure :)
 one year ago
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