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bookdweller Group Title

graph the system of linear inequalities. Then state two possible solutions. y> 2x + 2 y< -3/2x - 5

  • one year ago
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  1. RadEn Group Title
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    can u graph a straight line equation y=mx+c ?

    • one year ago
  2. bookdweller Group Title
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    No we just started this unit.

    • one year ago
  3. sarena89 Group Title
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    first y=2x+2 y=-3/2x-5

    • one year ago
  4. bookdweller Group Title
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    Okay, I'm following along so far.

    • one year ago
  5. sarena89 Group Title
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    |dw:1355666109106:dw|

    • one year ago
  6. sarena89 Group Title
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    and u make it anotther equation like me ok.

    • one year ago
  7. richyw Group Title
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    • one year ago
  8. richyw Group Title
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    so anything in the dark red would satisfy both inequalities

    • one year ago
  9. richyw Group Title
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    the blue is \(y>2x+2\) and the red is \(y<−\frac32 x−5\)

    • one year ago
  10. richyw Group Title
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    so all you have to do is graph the lines \(y=2x+2\) and \(y=-\frac32 x-5\) (I would use a dotted line for \(>\) or \(<\) and a solid line for \(\geq\) or \(\leq\)). Then shade in above or below the line depending what is required. Then your solutions will look like that graph, and where the shading overlaps is where you get a solution

    • one year ago
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