graph the system of linear inequalities. Then state two possible solutions. y> 2x + 2 y< -3/2x - 5

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

graph the system of linear inequalities. Then state two possible solutions. y> 2x + 2 y< -3/2x - 5

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

can u graph a straight line equation y=mx+c ?
No we just started this unit.
first y=2x+2 y=-3/2x-5

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Okay, I'm following along so far.
|dw:1355666109106:dw|
and u make it anotther equation like me ok.
so anything in the dark red would satisfy both inequalities
the blue is \(y>2x+2\) and the red is \(y<−\frac32 x−5\)
so all you have to do is graph the lines \(y=2x+2\) and \(y=-\frac32 x-5\) (I would use a dotted line for \(>\) or \(<\) and a solid line for \(\geq\) or \(\leq\)). Then shade in above or below the line depending what is required. Then your solutions will look like that graph, and where the shading overlaps is where you get a solution

Not the answer you are looking for?

Search for more explanations.

Ask your own question