## anonymous 3 years ago determine the coefficient of x^5 in the expression (2x-3)^8 help pls!!

1. anonymous

going with binomial theorem$(a+b)^n=\sum_{k=0}^{n} \binom{n}{k} a^k b^{n-k}$and setting a=2x ,b=-3 and n=8 ... will be your start point

2. anonymous

$\sum_{k=0}^{8} \left(\begin{matrix}8 \\ 5\end{matrix}\right) 2^5 (-3) ^3 x^5$ Is this is?

3. anonymous

u just need to evaluate one term of the sum and its where k equals to 5 so just $\left(\begin{matrix}8 \\ 5\end{matrix}\right) 2^5 (-3) ^3 x^5$