anonymous
  • anonymous
Does anyone now the table for the polar equation -6t(t is degree or radians)? No any helpful websites to help me get the table for this
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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richyw
  • richyw
what are you asking?
anonymous
  • anonymous
I am asking for the table for the polar equation -6t
tkhunny
  • tkhunny
There is no such thing as "the table". This explains why you cannot find it. Can you provide more information? Is there a specific problem you are working on?

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More answers

richyw
  • richyw
you want to make a table of cartesian coordinates for the polar function \(r(t)=-6t\) ?
anonymous
  • anonymous
@richyw yes
tkhunny
  • tkhunny
Notice richyw's use of the phrase "a table". You can make a table on any values you like. This is why "the table" doesn't exist.
anonymous
  • anonymous
Okay. So I am just basically looking for the coordinates of this equation
richyw
  • richyw
you could make a table of the polar coordinates. so for whatever angle t, you would have whatever radius r. or you could convert these coordinates to cartesian values, which would have x and y values being compared.
richyw
  • richyw
either way all you are doing is solving this equation for a few values.
anonymous
  • anonymous
No I have polar graph paper and all i need is like the points.
richyw
  • richyw
ok I see. so then you just directly solve this. choose whatever values of t that you want and then you will get the r value directly from the equation
anonymous
  • anonymous
Can you give me an example? If you don't mind
richyw
  • richyw
alright well the first point I would do would be at an angle of 0. so\[r(0)=-6(0)=0\] so you know that point will have angle 0 radius 0 (the origin)
richyw
  • richyw
how many points do you want?
anonymous
  • anonymous
I am going by 30 degrees so until 360
richyw
  • richyw
are you sure this is in degrees? usually I would assume radians unless it specified.
anonymous
  • anonymous
well radians will be find also
richyw
  • richyw
not that is makes a difference for the shape though
anonymous
  • anonymous
I understand but I am just trying to graph it
richyw
  • richyw
ok well then go 30 degrees more (\(\pi/3\) radians) plug it in \(r(\pi/3)=-6(\pi/3)\) so \(r=-2\pi\)
richyw
  • richyw
then plug in \(2\pi/3\) etc until you reach \(2\pi\)
sirm3d
  • sirm3d
uhm, 30 degrees is \(\pi /6\)
richyw
  • richyw
haha oops yup
anonymous
  • anonymous
Your fine you did 60 degrees
richyw
  • richyw
yup do what I said but every \(\pi/6\)
richyw
  • richyw
I make that mistake so often...
anonymous
  • anonymous
It's fine we can't remember everything
richyw
  • richyw
what I would do if I was you is calculate \(2\pi\) first and then it will give you an idea of the scale you need to use for the graph. because it's going to be a spiral shaped thing
richyw
  • richyw
anonymous
  • anonymous
Yes I have a art math project I already drew my flower
anonymous
  • anonymous
Hey can you convert that to radians because it will make my day much easier
richyw
  • richyw
that's already in radians
anonymous
  • anonymous
it is
richyw
  • richyw
yes if it was in degrees you would have much larger values of r!
anonymous
  • anonymous
yes that's true
richyw
  • richyw
I suppose if you wanted to see the radius scale in terms of fractions of pi I could open up octave. but you are gonna need to make the table of values anyways if that's what's required...
anonymous
  • anonymous
it is
sirm3d
  • sirm3d
here's a graph of the polar equation \(r(t) = 6t\) in the interval \(0 \leq t \leq 2\pi\)
1 Attachment
anonymous
  • anonymous
Thanks

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