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abbie1
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PLEASE HELP! A plane took 5 hours to get from Omaha to San Francisco with a tailwind of 28 mph. It took 6 hours to make the return trip with a headwind of the same speed, 28 mph. How fast was the plane traveling in still air?
 one year ago
 one year ago
abbie1 Group Title
PLEASE HELP! A plane took 5 hours to get from Omaha to San Francisco with a tailwind of 28 mph. It took 6 hours to make the return trip with a headwind of the same speed, 28 mph. How fast was the plane traveling in still air?
 one year ago
 one year ago

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abbie1 Group TitleBest ResponseYou've already chosen the best response.0
how did you calculate that? are you sure?? Thanks!!!
 one year ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 ?? do you know how to solve this??
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
and 1680 i think is too far
 one year ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
i set up (5p+28)=6(p28)..
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
close, i think it should be \[5(p+28)=6(p28)\]
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if you call "p" the rate
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yeah what you said at first
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
second
 one year ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
Yeah but then when you simplify it's 28 and thats not an answer..
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
oh i could be wrong, i jumped the gun maybe 1680 is the right answer
 one year ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
but how do you get that?!?!?!
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
lets solve \[5(x+28)=6(x28)\] \[5x+140=6x168\] \[140=x168\] \[x=308\] so the rate is 308 miles per hour, but that is not the distance, that is the rate
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
to find the distance replace the rate of 308 in either expression for example \[5(308+28)=5\times 336=1680\] as stated above
 one year ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
THANK YOU!! but that is the rate in still air as well?
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
@Anyssah was right , i jumped the gun
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
the rate in still air is 308 mph, yes. the distance is therefore 1680
 one year ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
Its not asking for the distance thought, its the rate it traveled in still air.
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
ok, then 308 mph is the right answer to that question
 one year ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
Thank you guys :)
 one year ago
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