## abbie1 Group Title PLEASE HELP! A plane took 5 hours to get from Omaha to San Francisco with a tailwind of 28 mph. It took 6 hours to make the return trip with a headwind of the same speed, 28 mph. How fast was the plane traveling in still air? one year ago one year ago

1. Anyssah

1680miles

2. abbie1

how did you calculate that? are you sure?? Thanks!!!

3. abbie1

@satellite73 ?? do you know how to solve this??

4. satellite73

yes

5. satellite73

and 1680 i think is too far

6. abbie1

i set up (5p+28)=6(p-28)..

7. abbie1

*5(p+28)

8. satellite73

close, i think it should be $5(p+28)=6(p-28)$

9. satellite73

if you call "p" the rate

10. satellite73

yeah what you said at first

11. satellite73

second

12. abbie1

Yeah but then when you simplify it's 28 and thats not an answer..

13. satellite73

oh i could be wrong, i jumped the gun maybe 1680 is the right answer

14. abbie1

but how do you get that?!?!?!

15. satellite73

lets solve $5(x+28)=6(x-28)$ $5x+140=6x-168$ $140=x-168$ $x=308$ so the rate is 308 miles per hour, but that is not the distance, that is the rate

16. satellite73

to find the distance replace the rate of 308 in either expression for example $5(308+28)=5\times 336=1680$ as stated above

17. abbie1

THANK YOU!! but that is the rate in still air as well?

18. satellite73

@Anyssah was right , i jumped the gun

19. satellite73

the rate in still air is 308 mph, yes. the distance is therefore 1680

20. abbie1

Its not asking for the distance thought, its the rate it traveled in still air.

21. satellite73

ok, then 308 mph is the right answer to that question

22. abbie1

Thank you guys :)