anonymous
  • anonymous
PLEASE HELP! A plane took 5 hours to get from Omaha to San Francisco with a tailwind of 28 mph. It took 6 hours to make the return trip with a headwind of the same speed, 28 mph. How fast was the plane traveling in still air?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
1680miles
anonymous
  • anonymous
how did you calculate that? are you sure?? Thanks!!!
anonymous
  • anonymous
@satellite73 ?? do you know how to solve this??

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yes
anonymous
  • anonymous
and 1680 i think is too far
anonymous
  • anonymous
i set up (5p+28)=6(p-28)..
anonymous
  • anonymous
*5(p+28)
anonymous
  • anonymous
close, i think it should be \[5(p+28)=6(p-28)\]
anonymous
  • anonymous
if you call "p" the rate
anonymous
  • anonymous
yeah what you said at first
anonymous
  • anonymous
second
anonymous
  • anonymous
Yeah but then when you simplify it's 28 and thats not an answer..
anonymous
  • anonymous
oh i could be wrong, i jumped the gun maybe 1680 is the right answer
anonymous
  • anonymous
but how do you get that?!?!?!
anonymous
  • anonymous
lets solve \[5(x+28)=6(x-28)\] \[5x+140=6x-168\] \[140=x-168\] \[x=308\] so the rate is 308 miles per hour, but that is not the distance, that is the rate
anonymous
  • anonymous
to find the distance replace the rate of 308 in either expression for example \[5(308+28)=5\times 336=1680\] as stated above
anonymous
  • anonymous
THANK YOU!! but that is the rate in still air as well?
anonymous
  • anonymous
@Anyssah was right , i jumped the gun
anonymous
  • anonymous
the rate in still air is 308 mph, yes. the distance is therefore 1680
anonymous
  • anonymous
Its not asking for the distance thought, its the rate it traveled in still air.
anonymous
  • anonymous
ok, then 308 mph is the right answer to that question
anonymous
  • anonymous
Thank you guys :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.