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abbie1
Group Title
PLEASE HELP! A plane took 5 hours to get from Omaha to San Francisco with a tailwind of 28 mph. It took 6 hours to make the return trip with a headwind of the same speed, 28 mph. How fast was the plane traveling in still air?
 2 years ago
 2 years ago
abbie1 Group Title
PLEASE HELP! A plane took 5 hours to get from Omaha to San Francisco with a tailwind of 28 mph. It took 6 hours to make the return trip with a headwind of the same speed, 28 mph. How fast was the plane traveling in still air?
 2 years ago
 2 years ago

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abbie1 Group TitleBest ResponseYou've already chosen the best response.0
how did you calculate that? are you sure?? Thanks!!!
 2 years ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73 ?? do you know how to solve this??
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
and 1680 i think is too far
 2 years ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
i set up (5p+28)=6(p28)..
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
close, i think it should be \[5(p+28)=6(p28)\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if you call "p" the rate
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
yeah what you said at first
 2 years ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
Yeah but then when you simplify it's 28 and thats not an answer..
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
oh i could be wrong, i jumped the gun maybe 1680 is the right answer
 2 years ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
but how do you get that?!?!?!
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
lets solve \[5(x+28)=6(x28)\] \[5x+140=6x168\] \[140=x168\] \[x=308\] so the rate is 308 miles per hour, but that is not the distance, that is the rate
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
to find the distance replace the rate of 308 in either expression for example \[5(308+28)=5\times 336=1680\] as stated above
 2 years ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
THANK YOU!! but that is the rate in still air as well?
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
@Anyssah was right , i jumped the gun
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
the rate in still air is 308 mph, yes. the distance is therefore 1680
 2 years ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
Its not asking for the distance thought, its the rate it traveled in still air.
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
ok, then 308 mph is the right answer to that question
 2 years ago

abbie1 Group TitleBest ResponseYou've already chosen the best response.0
Thank you guys :)
 2 years ago
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