Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
A certain test is used to screen for Alzheimers disease. People with and without the disease were sampled and the following table resulted. Given the general Alzheimer disease rate is 0.001, what is the probability that a randomly selected individual will have an erroneous test result? [Hint: an error occurs if the individual has the disease and receives a negative test result or…?]
Test Disease No Disease Total
+ 436 5 441
 14 495 509
Total 450 500 950
 one year ago
 one year ago
A certain test is used to screen for Alzheimers disease. People with and without the disease were sampled and the following table resulted. Given the general Alzheimer disease rate is 0.001, what is the probability that a randomly selected individual will have an erroneous test result? [Hint: an error occurs if the individual has the disease and receives a negative test result or…?] Test Disease No Disease Total + 436 5 441  14 495 509 Total 450 500 950
 one year ago
 one year ago

This Question is Closed

kropot72Best ResponseYou've already chosen the best response.1
Let P(A) = probability that the individual has the disease and receives a false negative result. \[P(A)=0.001\times \frac{5}{441}\] Let P(B) = probability that the individual does not have the disease and receives a false positive result. \[P(B)=(10.001)\times \frac{14}{509}=0.999\times \frac{14}{509}\] Event A and event B cannot happen together therefore the events are mutually exclusive. P(A or B) = P(A) + P(B) = probability of an erroneous test result.
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
i don't get the right answer. the answer should be 0.010021
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
There is only 1 chance in 1000 that a randomly selected individual has the disease. Assuming that the individual does not have the disease and is tested, the probability of a false positive (based on the sampling result) is 14/509 = 0.0275. The probability that a randomly selected selected individual has the disease and gives a false negative will add to the value of 0.0275. Assuming that the question has been stated with no errors, I must conclude that the answer 0.010021 is incorrect. Have you any other way of checking the answer?
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
well, maybe. i was told the answer was 0.010021. that's okay. i will skip this question
 one year ago

UnkleRhaukusBest ResponseYou've already chosen the best response.2
@kropot72, your woking is great, i think you just read the table wrong ( its a trick table to read ) \[P(A)=0.001\times\frac{14}{450}\approx0.000031\] \[P(B)=(10.001)\times\frac5{500}\approx0.00999\]
 one year ago

kropot72Best ResponseYou've already chosen the best response.1
@UnkleRhaukus Thank you for your help. Your reading of the table sure gets the given correct answer. With more thought I am sure I will get my head around the correct reading of the table :)
 one year ago

soccergal12Best ResponseYou've already chosen the best response.0
thank you. that makes more sense
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.