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In the figure, AB//CD and they are 4 cm apart. P and Q are the midpoints of AB and CD respectively. If AB=16 cm and CD=12 cm, find:
(a) the length of OP
(b) the radius of the circle.
 one year ago
 one year ago
In the figure, AB//CD and they are 4 cm apart. P and Q are the midpoints of AB and CD respectively. If AB=16 cm and CD=12 cm, find: (a) the length of OP (b) the radius of the circle.
 one year ago
 one year ago

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kryton1212Best ResponseYou've already chosen the best response.0
dw:1355634883499:dw
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
dw:1355637343376:dw
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
dw:1355637938345:dw
 one year ago

kryton1212Best ResponseYou've already chosen the best response.0
I have think about it but I cannot do furthermore...
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
Right triangle AOP has legs AP and OP and hypotenuse OA Right triangle COQ has legs CQ and OQ and hypotenuse OC Because they're both radii, OA = OC = r For right triangle AOP, (OP)^2 + (AP)^2 = r^2 For right triangle COQ, (CQ)^2 + (OQ)^2 = r^2 By substitution, (OP)^2 + (AP)^2 = (CQ)^2 + (OQ)^2 Substitue values we know: (OP)^2 + 64 = 36 + (OP + 4)^2 (OP)^2 + 64 = 36 + (OP)^2 + 8(OP) + 16 Subtract (OP)^2 from both sides 64 = 36 + 8(OP) + 16 8(OP) = 12 OP = 1.5
 one year ago

kryton1212Best ResponseYou've already chosen the best response.0
got it. then I know part b :) thank you
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
(AP)^2 + (OP)^2 = r^2 64 + (1.5)^2 = r^2 r^2 = 66.25 r^2 = 265/4 r = sqrt(265)/2
 one year ago

kryton1212Best ResponseYou've already chosen the best response.0
thank you very much
 one year ago

mathstudent55Best ResponseYou've already chosen the best response.1
You're very welcome.
 one year ago
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