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kryton1212
 3 years ago
In the figure, AB//CD and they are 4 cm apart. P and Q are the midpoints of AB and CD respectively. If AB=16 cm and CD=12 cm, find:
(a) the length of OP
(b) the radius of the circle.
kryton1212
 3 years ago
In the figure, AB//CD and they are 4 cm apart. P and Q are the midpoints of AB and CD respectively. If AB=16 cm and CD=12 cm, find: (a) the length of OP (b) the radius of the circle.

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kryton1212
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1355634883499:dw

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1355637343376:dw

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1355637938345:dw

kryton1212
 3 years ago
Best ResponseYou've already chosen the best response.0I have think about it but I cannot do furthermore...

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1Right triangle AOP has legs AP and OP and hypotenuse OA Right triangle COQ has legs CQ and OQ and hypotenuse OC Because they're both radii, OA = OC = r For right triangle AOP, (OP)^2 + (AP)^2 = r^2 For right triangle COQ, (CQ)^2 + (OQ)^2 = r^2 By substitution, (OP)^2 + (AP)^2 = (CQ)^2 + (OQ)^2 Substitue values we know: (OP)^2 + 64 = 36 + (OP + 4)^2 (OP)^2 + 64 = 36 + (OP)^2 + 8(OP) + 16 Subtract (OP)^2 from both sides 64 = 36 + 8(OP) + 16 8(OP) = 12 OP = 1.5

kryton1212
 3 years ago
Best ResponseYou've already chosen the best response.0got it. then I know part b :) thank you

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1(AP)^2 + (OP)^2 = r^2 64 + (1.5)^2 = r^2 r^2 = 66.25 r^2 = 265/4 r = sqrt(265)/2

mathstudent55
 3 years ago
Best ResponseYou've already chosen the best response.1You're very welcome.
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