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where are you stuck ?

I dont know anything at all to be honest.

About this topic.

I dont get anything =/ second all Just go to shift x to other side right and makes t y=x-8

y=8-x

x^2+(8-x)^2=24

x^2+64-16x+x^2=24

2x^2-16x+40=0

x^2-8x+20=0

so y cnt be x-8 but has to 8-x?

yes..

(x-10)(x+2)=0
x=10
x=-2

so those will be the solutions right?

find b's also..

I meant y

because these eq. are two variable..

could you just guide me through like what to do?

thank you!

hold on I made a mistake..

until this it is true, but I made a mistake when I factored it out..
x^2-8x+20=0

ax^2+bx+c=0
d=b^2-4ac
d=8^2-4*1*20=-16<0 no real solution..

it means that they are not crossing each other..

sorry about that..

root are complex number..

its okay thanks for your time, really appreciate all this walk through.

http://www.wolframalpha.com/input/?i=solve+x^2%2By^2%3D24%2Cx%2By%3D8

you can see it here

yes thank you!

np