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evaluate indefinite integrals intergral tan^2x Sec^2x dx

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take the derivative
derivative of tanx?

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Other answers:

both sides
what is it
derivative of tna is sec^2x
subs. them in int.
if tanx=u then what is tan^2x
u sqre
then what is your new int. depends on only u
int. tan^2x Sec^2x dx sec^2xdx=du tan^2x=u^2
csc x^3/ 3 ?
what are they in u
u^2 . du
solve that integral..
1/3 tan^3 x+c ?
you got it..
but i have one question though
shoot it..
did not get it,s orry
they are the same thing but just different letter..
oh okay.
dx or du they are just saying that you are taking int. depends on that variable
you can assume that x is just a constant in here..
okay,thanks. i have another problem, will you help me with that?
take derivative
how do you decide which one is "U"?
because I can see that derivative sinx =cosxdx and it is above
derivative of sin theta = cos theta d theta
but it is sinsqrt theta
cos sqrt theta d theta
one more thing youre missing
what is it?
derivative of sqrt theta
how did you get that half?
what is your new integral..
1/2 integral 1/sin sqrt theta +c?
what is int. 1/x dx=?
in your case lnu+c put u back in
I gotta go, any question..
so,thats the ans ? after putting the u?
yes, ln(sin sqrt theta)+c is the answer..
okay,thanks a lot

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