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roselin

  • 2 years ago

evaluate indefinite integrals integral squareroot x^4/ x^3-1 dx

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  1. roselin
    • 2 years ago
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    what is it ?

  2. roselin
    • 2 years ago
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    thanks

  3. RadEn
    • 2 years ago
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    is the x^3-1 in the sqrt also or no ??

  4. roselin
    • 2 years ago
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    yes, it is.

  5. RadEn
    • 2 years ago
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    |dw:1355676028137:dw|

  6. roselin
    • 2 years ago
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    okay,

  7. RadEn
    • 2 years ago
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    now, use int by subs let u=x^3-1 du = 3x^2 dx or x^2 dx = 1/3 du continue it.....

  8. roselin
    • 2 years ago
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    -1/3 intergral 1/ sqrt of u * du

  9. RadEn
    • 2 years ago
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    miss (-) sign, how come this ?

  10. roselin
    • 2 years ago
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    i took du as -3x^2

  11. RadEn
    • 2 years ago
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    derivative of x^3 is 3x^2, right ?

  12. roselin
    • 2 years ago
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    yes

  13. RadEn
    • 2 years ago
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    so, why becomes (-) ?

  14. roselin
    • 2 years ago
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    well, i wrote the problem as 1-x^3 instead of x^3 -1

  15. RadEn
    • 2 years ago
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    lol, hahaha...

  16. roselin
    • 2 years ago
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    hmm

  17. RadEn
    • 2 years ago
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    so, the original problem is over x^3-1 or 1-x^3 ?

  18. roselin
    • 2 years ago
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    it is x^3 -1

  19. RadEn
    • 2 years ago
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    ok, therefore the integration can be |dw:1355676826761:dw|

  20. RadEn
    • 2 years ago
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    i just gave u +c :), for the rest let try it

  21. roselin
    • 2 years ago
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    u= x^3 -1 here

  22. RadEn
    • 2 years ago
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    yes

  23. RadEn
    • 2 years ago
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    because i have saw ur problem is .... over x^3-1, but experiment gave u 1-x^3

  24. roselin
    • 2 years ago
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    i know

  25. roselin
    • 2 years ago
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    and i put it in the wolfram thing, got some different ans

  26. RadEn
    • 2 years ago
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    what's the result of int above, dont use wolfram first

  27. roselin
    • 2 years ago
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    (u) ^-1/2 +1/ -1/2+1

  28. RadEn
    • 2 years ago
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    where is the 1/3 ?

  29. roselin
    • 2 years ago
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    (x^3-1)+c

  30. roselin
    • 2 years ago
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    What do I do with that 1/3?

  31. roselin
    • 2 years ago
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    can you please write down the whole problem and show how it works, if you do not mind then

  32. roselin
    • 2 years ago
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    i am kind of confused

  33. RadEn
    • 2 years ago
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    |dw:1355677696473:dw|

  34. RadEn
    • 2 years ago
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    got it ?

  35. roselin
    • 2 years ago
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    how did u get that 2u?

  36. RadEn
    • 2 years ago
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    1/(-1/2 + 1) = 1/(1/2) = 1 * 2/1 = 2 right ?

  37. roselin
    • 2 years ago
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    yeah, sorry

  38. roselin
    • 2 years ago
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    i have another problem, will you guide me through that one? i will try solving it and show it to you.

  39. RadEn
    • 2 years ago
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    nopes... now, subtitute back that u=x^3-1 so, the answer be 2/3 (x^3-1)^(1/2) + c or 2/3*sqrt(x^3-1) + c

  40. RadEn
    • 2 years ago
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    wolfram is same with the answer above :)

  41. roselin
    • 2 years ago
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    k.

  42. roselin
    • 2 years ago
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    okay

  43. roselin
    • 2 years ago
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    thank you.

  44. RadEn
    • 2 years ago
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    very welcome

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