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 2 years ago
Given that a + b(1+x)^3 + c(1+2x)^3 + d(1+3x)^3 = x^3,
find the values for a, b c, d.
 2 years ago
Given that a + b(1+x)^3 + c(1+2x)^3 + d(1+3x)^3 = x^3, find the values for a, b c, d.

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tanvidais13
 2 years ago
Best ResponseYou've already chosen the best response.0so do i need to expand the things using binomial, or what??

tanvidais13
 2 years ago
Best ResponseYou've already chosen the best response.0because it's a mixture of AP's and GP's.

mustry
 2 years ago
Best ResponseYou've already chosen the best response.0use binomial please if confused ask me please

tanvidais13
 2 years ago
Best ResponseYou've already chosen the best response.0so i expanded it, but everything is in b's and c's and d's.

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1so use systems of equations.

tanvidais13
 2 years ago
Best ResponseYou've already chosen the best response.0but then everything is equated to 0.

tanvidais13
 2 years ago
Best ResponseYou've already chosen the best response.0does anyone have any idea as to what i could do here??

mustry
 2 years ago
Best ResponseYou've already chosen the best response.0x^3+d (19 x27 x^227 x^3)+b (13 x3 x^2x^3)c(1+2 x)^3=a

slaaibak
 2 years ago
Best ResponseYou've already chosen the best response.1a + b(1+x)^3 + c(1+2x)^3 + d(1+3x)^3 = x^3 a + b(1 + 3x + 3x^2 + x^3) + c(1 + 6x + 12x^2 + 8x^3) + d(1 + 9x + 27x^2 + 27x^3)=x^3 Now leave the RHS, and group the LHS accordingly: (b + 8c + 27c)x^3 + (3b + 12c + 27d)x^2 + (3b + 6c + 9c)x + (a + b + c + d) = x^3 it follows that: b + 8c + 27c=1 3b + 12c + 27d=0 3b + 6c + 9c=0 a + b + c + d =0 solve that.
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