anonymous
  • anonymous
Given that a + b(1+x)^3 + c(1+2x)^3 + d(1+3x)^3 = x^3, find the values for a, b c, d.
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
so do i need to expand the things using binomial, or what??
anonymous
  • anonymous
because it's a mixture of AP's and GP's.
anonymous
  • anonymous
use binomial please if confused ask me please

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so i expanded it, but everything is in b's and c's and d's.
slaaibak
  • slaaibak
so use systems of equations.
anonymous
  • anonymous
but then everything is equated to 0.
anonymous
  • anonymous
does anyone have any idea as to what i could do here??
anonymous
  • anonymous
x^3+d (-1-9 x-27 x^2-27 x^3)+b (-1-3 x-3 x^2-x^3)-c(1+2 x)^3=a
slaaibak
  • slaaibak
a + b(1+x)^3 + c(1+2x)^3 + d(1+3x)^3 = x^3 a + b(1 + 3x + 3x^2 + x^3) + c(1 + 6x + 12x^2 + 8x^3) + d(1 + 9x + 27x^2 + 27x^3)=x^3 Now leave the RHS, and group the LHS accordingly: (b + 8c + 27c)x^3 + (3b + 12c + 27d)x^2 + (3b + 6c + 9c)x + (a + b + c + d) = x^3 it follows that: b + 8c + 27c=1 3b + 12c + 27d=0 3b + 6c + 9c=0 a + b + c + d =0 solve that.

Looking for something else?

Not the answer you are looking for? Search for more explanations.