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Given that a + b(1+x)^3 + c(1+2x)^3 + d(1+3x)^3 = x^3,
find the values for a, b c, d.
 one year ago
 one year ago
Given that a + b(1+x)^3 + c(1+2x)^3 + d(1+3x)^3 = x^3, find the values for a, b c, d.
 one year ago
 one year ago

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tanvidais13Best ResponseYou've already chosen the best response.0
so do i need to expand the things using binomial, or what??
 one year ago

tanvidais13Best ResponseYou've already chosen the best response.0
because it's a mixture of AP's and GP's.
 one year ago

mustryBest ResponseYou've already chosen the best response.0
use binomial please if confused ask me please
 one year ago

tanvidais13Best ResponseYou've already chosen the best response.0
so i expanded it, but everything is in b's and c's and d's.
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
so use systems of equations.
 one year ago

tanvidais13Best ResponseYou've already chosen the best response.0
but then everything is equated to 0.
 one year ago

tanvidais13Best ResponseYou've already chosen the best response.0
does anyone have any idea as to what i could do here??
 one year ago

mustryBest ResponseYou've already chosen the best response.0
x^3+d (19 x27 x^227 x^3)+b (13 x3 x^2x^3)c(1+2 x)^3=a
 one year ago

slaaibakBest ResponseYou've already chosen the best response.1
a + b(1+x)^3 + c(1+2x)^3 + d(1+3x)^3 = x^3 a + b(1 + 3x + 3x^2 + x^3) + c(1 + 6x + 12x^2 + 8x^3) + d(1 + 9x + 27x^2 + 27x^3)=x^3 Now leave the RHS, and group the LHS accordingly: (b + 8c + 27c)x^3 + (3b + 12c + 27d)x^2 + (3b + 6c + 9c)x + (a + b + c + d) = x^3 it follows that: b + 8c + 27c=1 3b + 12c + 27d=0 3b + 6c + 9c=0 a + b + c + d =0 solve that.
 one year ago
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