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mitchelsewbaran Group Title

What is the simplified form of the equation below?

  • one year ago
  • one year ago

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  1. yummydum Group Title
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    i look below i no see equation o.o

    • one year ago
  2. mitchelsewbaran Group Title
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    hold on!

    • one year ago
  3. yummydum Group Title
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    HOLDING ON!! D:

    • one year ago
  4. mitchelsewbaran Group Title
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    • one year ago
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  5. yummydum Group Title
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    dividing a fraction by a fraction is the same as multiplying a fraction by the reciprocal of another fraction...like this: \[\huge{{a\over b}\over{c\over d}}~~~~~\implies~~~~~{{a\over b}\times{d\over c}}\]

    • one year ago
  6. yummydum Group Title
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    so in your case its:\[\huge{{12x\over x^2+6x+9}\over{4x^2\over x^2-9}}~~~~~\implies~~~~~{{12x\over x^2+6x+9}\times{x^2-9\over4x^2}}\] so now just cross multiply

    • one year ago
  7. mitchelsewbaran Group Title
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    here are the answers

    • one year ago
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  8. mitchelsewbaran Group Title
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    so it's the 4th one?

    • one year ago
  9. yummydum Group Title
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    one sec :)

    • one year ago
  10. yummydum Group Title
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    \[\large{{12x\over x^2+6x+9}\times{x^2-9\over4x^2}}~~~~~\implies~~~~{{12x\times(x^2-9)}\over{x^2+6x+9\times (4x^2)}}\]sorry i wrote that wrong...this gives you:\[\large{12x^3-108x\over 4x^4+24x^3+36x^2}\]simpllify that

    • one year ago
  11. mitchelsewbaran Group Title
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    i simplified it. it's the 2nd one

    • one year ago
  12. yummydum Group Title
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    yup! :D

    • one year ago
  13. mitchelsewbaran Group Title
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    thnx, bro!

    • one year ago
  14. yummydum Group Title
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    no problem!

    • one year ago
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