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roastedchickenwings

  • 2 years ago

Prove that the fractional loss in kinetic energy for the ball-pendulum system is given by equation n=1-m/m+M

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  1. Jemurray3
    • 2 years ago
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    This doesn't make sense without context.

  2. roastedchickenwings
    • 2 years ago
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    frictional loss=0.8099 and 0.7963. for silver and brass respectively

  3. Jemurray3
    • 2 years ago
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    Context, meaning you need to explain what the system is.

  4. roastedchickenwings
    • 2 years ago
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    how would i explain it. that was the question on my lab book. I apologize for being vague

  5. Jemurray3
    • 2 years ago
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    I would assume the question pertains to a system that was described somewhere...

  6. roastedchickenwings
    • 2 years ago
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    does it apply to the prior question?

  7. roastedchickenwings
    • 2 years ago
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    1. A 15 g bullet is fired horizontally into a block of wood with mass of 2.5kg and embedded in the block. Initially the block of wood hangs vertically and the impact causes the block to swing so that its center of mass raises 15 cm. Find velocity of bullet just before impact.

  8. Jemurray3
    • 2 years ago
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    There you go. 1) Use the velocity you found to calculate the kinetic energy of the bullet before it strikes the block 2) Use the conservation of momentum to find the kinetic energy of the block and bullet together right after it hits 3) Compare them

  9. roastedchickenwings
    • 2 years ago
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    thank you

  10. roastedchickenwings
    • 2 years ago
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    this is what i got so far Kinetic Energy of ball just before collision is Ki = (1/2)mv^2 Kinetic Energy of Ball+Pendulum just after collision is; Kf = (1/2)(m+M)u^2 Fractional ratio is; Kf/Ki = [(m+M)/m](u^2/v^2) Kf = [(m+M)/m](u^2/v^2)Ki Fractional Loss is; (Ki - Kf)/Ki = 1 - [(m+M)/m](u^2/v^2) Using conservation of momentum just before & just after the collision to find relation between v & u; mv = (m+M)u u = mv/(m+M) u/v = m/(m+M) u^2/v^2 = m^2/(m+M)^2 what should the answer be. help!

  11. Jemurray3
    • 2 years ago
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    The answer is in the question..... And if you plug what you just calculated in, then that would be correct.

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