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 2 years ago
Prove that the fractional loss in kinetic energy for the ballpendulum system is given by equation n=1m/m+M
 2 years ago
Prove that the fractional loss in kinetic energy for the ballpendulum system is given by equation n=1m/m+M

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Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1This doesn't make sense without context.

roastedchickenwings
 2 years ago
Best ResponseYou've already chosen the best response.0frictional loss=0.8099 and 0.7963. for silver and brass respectively

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1Context, meaning you need to explain what the system is.

roastedchickenwings
 2 years ago
Best ResponseYou've already chosen the best response.0how would i explain it. that was the question on my lab book. I apologize for being vague

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1I would assume the question pertains to a system that was described somewhere...

roastedchickenwings
 2 years ago
Best ResponseYou've already chosen the best response.0does it apply to the prior question?

roastedchickenwings
 2 years ago
Best ResponseYou've already chosen the best response.01. A 15 g bullet is fired horizontally into a block of wood with mass of 2.5kg and embedded in the block. Initially the block of wood hangs vertically and the impact causes the block to swing so that its center of mass raises 15 cm. Find velocity of bullet just before impact.

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1There you go. 1) Use the velocity you found to calculate the kinetic energy of the bullet before it strikes the block 2) Use the conservation of momentum to find the kinetic energy of the block and bullet together right after it hits 3) Compare them

roastedchickenwings
 2 years ago
Best ResponseYou've already chosen the best response.0this is what i got so far Kinetic Energy of ball just before collision is Ki = (1/2)mv^2 Kinetic Energy of Ball+Pendulum just after collision is; Kf = (1/2)(m+M)u^2 Fractional ratio is; Kf/Ki = [(m+M)/m](u^2/v^2) Kf = [(m+M)/m](u^2/v^2)Ki Fractional Loss is; (Ki  Kf)/Ki = 1  [(m+M)/m](u^2/v^2) Using conservation of momentum just before & just after the collision to find relation between v & u; mv = (m+M)u u = mv/(m+M) u/v = m/(m+M) u^2/v^2 = m^2/(m+M)^2 what should the answer be. help!

Jemurray3
 2 years ago
Best ResponseYou've already chosen the best response.1The answer is in the question..... And if you plug what you just calculated in, then that would be correct.
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