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BeautyQueen327

  • 3 years ago

solve: ln(x^2) - ln 7=0

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  1. slaaibak
    • 3 years ago
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    easiest method would be to say: \[\ln({x^2 \over 7}) = 0\] and we know the ln 1 = 0 so x^2 / 7 = 1 \[x = \pm \sqrt7\]

  2. BeautyQueen327
    • 3 years ago
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    thank you thank you thank you!

  3. slaaibak
    • 3 years ago
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    it's my pleasure :)

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