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slaaibak Group TitleBest ResponseYou've already chosen the best response.1
Nope other way around.. \[\tan^2 x + 1 = \sec^2x\]
 one year ago

saifoo.khan Group TitleBest ResponseYou've already chosen the best response.0
I knew it i was making some mistake!
 one year ago

Hero Group TitleBest ResponseYou've already chosen the best response.1
\[\tan^2x + 1 = \frac{\sin^2x}{\cos^2x} + \frac{\cos^2x}{\cos^2x} = \frac{1}{cos^2x} = \sec^2x\]
 one year ago

meri258 Group TitleBest ResponseYou've already chosen the best response.0
Thank you all! I got it!
 one year ago
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