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\[∫(24lnx)/xdx=∫(24lnx)d(lnx)=...\]
Hmm.. The idea is to let u = lnx , du= ... dx Then do the substitution and integrate it.
right now I have 24x +xlnx-1 + lnx

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|dw:1355723590484:dw|
can you integrate that?
|dw:1355723775094:dw|
integrate from there
|dw:1355723857099:dw|
is that right
|dw:1355723958311:dw|
ok integrate of ln x = xlnx -1 ?
do u subsitution
24 integrate lnx 1/x is final ?
|dw:1355724026428:dw|
thankss ! that made everything much clear, but how did you know to use the u^2/ 2?
you have to add 1 to the power then divided..let say if you have \[\int\limits(x^2)\] when you intergrate it will be \[\frac{ x ^{2+1} }{ 2+1 }\] \[\frac{ x^3 }{ 3 }\]
|dw:1355724577063:dw|
Thanks fellas
like @Callisto says dont forget the C

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