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lovelymultani

  • 3 years ago

∫(24lnx)/x

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  1. Callisto
    • 3 years ago
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    \[∫(24lnx)/xdx=∫(24lnx)d(lnx)=...\]

  2. Callisto
    • 3 years ago
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    Hmm.. The idea is to let u = lnx , du= ... dx Then do the substitution and integrate it.

  3. lovelymultani
    • 3 years ago
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    right now I have 24x +xlnx-1 + lnx

  4. winterfez
    • 3 years ago
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    |dw:1355723590484:dw|

  5. winterfez
    • 3 years ago
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    can you integrate that?

  6. winterfez
    • 3 years ago
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    |dw:1355723775094:dw|

  7. winterfez
    • 3 years ago
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    integrate from there

  8. lovelymultani
    • 3 years ago
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    |dw:1355723857099:dw|

  9. lovelymultani
    • 3 years ago
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    is that right

  10. winterfez
    • 3 years ago
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    |dw:1355723958311:dw|

  11. lovelymultani
    • 3 years ago
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    ok integrate of ln x = xlnx -1 ?

  12. winterfez
    • 3 years ago
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    do u subsitution

  13. lovelymultani
    • 3 years ago
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    24 integrate lnx 1/x is final ?

  14. winterfez
    • 3 years ago
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    |dw:1355724026428:dw|

  15. lovelymultani
    • 3 years ago
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    thankss ! that made everything much clear, but how did you know to use the u^2/ 2?

  16. winterfez
    • 3 years ago
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    you have to add 1 to the power then divided..let say if you have \[\int\limits(x^2)\] when you intergrate it will be \[\frac{ x ^{2+1} }{ 2+1 }\] \[\frac{ x^3 }{ 3 }\]

  17. Callisto
    • 3 years ago
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    |dw:1355724577063:dw|

  18. lovelymultani
    • 3 years ago
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    Thanks fellas

  19. winterfez
    • 3 years ago
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    like @Callisto says dont forget the C

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