Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing

This Question is Closed

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
I know the square root argument must be grater to 0 but I can solve the inside for x> 0 .
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
@Callisto @UnkleRhaukus
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
@jim_thompson5910
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt{x^4+3x^2+4}+1\]
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
That's the right one sorry :P .
 one year ago

Aylin Group TitleBest ResponseYou've already chosen the best response.1
\[\sqrt{x^{4}+3x^{2}+4}\] \[x^{4}+3x^{2}+4 \ge 0\]I'm going to try to divide the equation by (x^2+1)\[\frac{ x^{4}+3x^{2}+4 }{ x^{2}+1 }=(x^{2}4)=(x+2)(x2)\](The above was done on paper since it would be too tedious to put in the calculation here). But this shows that \[x^{4}+3x^{2}+4=(x+2)(x2)(x^{2}+1) \ge 0\]You should be able to get the rest. (x^2+1 was attempted since all of the powers of x were divisible by 2, and all of the coefficients had 1 as their only common factor).
 one year ago

Dido525 Group TitleBest ResponseYou've already chosen the best response.0
Thanks a lot :) .
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.