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sha0403
Group Title
can u all help me to differentiate this, i try but still did not get it... find dy/dx and d^2y/dx^2question:
y^2=ye^(x^2)+2x
 one year ago
 one year ago
sha0403 Group Title
can u all help me to differentiate this, i try but still did not get it... find dy/dx and d^2y/dx^2question: y^2=ye^(x^2)+2x
 one year ago
 one year ago

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winterfez Group TitleBest ResponseYou've already chosen the best response.1
\[2yy'=y'e ^{x^2}+2\] \[2yy'=y'e ^{x^2}+y2xe ^{x^2}+2\] \[2yy'y'e ^{x^2}=y2xe ^{x^2}+2\] \[y'(2ye ^{x^2})=y2xe ^{x^2}+2\] \[y'=\frac{ y2xe ^{x^2}+2 }{ 2ye ^{x^2} }\]
 one year ago

winterfez Group TitleBest ResponseYou've already chosen the best response.1
I'm assuming \[\frac{ dy^2 }{ dx^2 }\] is second derivative?
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
thanks,, but to differentiate the answer again i have no idea..
 one year ago

winterfez Group TitleBest ResponseYou've already chosen the best response.1
k let me try...it going to be long
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
ok tq so much
 one year ago

winterfez Group TitleBest ResponseYou've already chosen the best response.1
\[y''=\frac{ (2y'xe ^{x^2}+2ye ^{x^2}+2xy(2x)e ^{x^2})(2ye ^{x^2})(y2xe ^{x^2}+2)(2y'2xe ^{x^2} }{ (2ye ^{x^2})^2 }\] \[\frac{ (2y'xe ^{x^2}+2ye ^{x^2}+4x^2ye ^{x^2})(2ye ^{x^2})(y2xe ^{x^2}+2)(2y'2xe ^{x^2}) }{ (2ye ^{x^2})^2 }\]
 one year ago

winterfez Group TitleBest ResponseYou've already chosen the best response.1
phewww this is what I got so far
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
the answer just like that?
 one year ago

sha0403 Group TitleBest ResponseYou've already chosen the best response.0
ok tq so much..now i get it
 one year ago
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