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can u all help me to differentiate this, i try but still did not get it... find dy/dx and d^2y/dx^2question:
y^2=ye^(x^2)+2x
 one year ago
 one year ago
can u all help me to differentiate this, i try but still did not get it... find dy/dx and d^2y/dx^2question: y^2=ye^(x^2)+2x
 one year ago
 one year ago

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winterfezBest ResponseYou've already chosen the best response.1
\[2yy'=y'e ^{x^2}+2\] \[2yy'=y'e ^{x^2}+y2xe ^{x^2}+2\] \[2yy'y'e ^{x^2}=y2xe ^{x^2}+2\] \[y'(2ye ^{x^2})=y2xe ^{x^2}+2\] \[y'=\frac{ y2xe ^{x^2}+2 }{ 2ye ^{x^2} }\]
 one year ago

winterfezBest ResponseYou've already chosen the best response.1
I'm assuming \[\frac{ dy^2 }{ dx^2 }\] is second derivative?
 one year ago

sha0403Best ResponseYou've already chosen the best response.0
thanks,, but to differentiate the answer again i have no idea..
 one year ago

winterfezBest ResponseYou've already chosen the best response.1
k let me try...it going to be long
 one year ago

winterfezBest ResponseYou've already chosen the best response.1
\[y''=\frac{ (2y'xe ^{x^2}+2ye ^{x^2}+2xy(2x)e ^{x^2})(2ye ^{x^2})(y2xe ^{x^2}+2)(2y'2xe ^{x^2} }{ (2ye ^{x^2})^2 }\] \[\frac{ (2y'xe ^{x^2}+2ye ^{x^2}+4x^2ye ^{x^2})(2ye ^{x^2})(y2xe ^{x^2}+2)(2y'2xe ^{x^2}) }{ (2ye ^{x^2})^2 }\]
 one year ago

winterfezBest ResponseYou've already chosen the best response.1
phewww this is what I got so far
 one year ago

sha0403Best ResponseYou've already chosen the best response.0
the answer just like that?
 one year ago

sha0403Best ResponseYou've already chosen the best response.0
ok tq so much..now i get it
 one year ago
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