A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing

This Question is Closed

giovkast
 2 years ago
Best ResponseYou've already chosen the best response.0\[{x1}, ...., {x6} = 15\]

giovkast
 2 years ago
Best ResponseYou've already chosen the best response.0\[\left(\begin{matrix}15 + 6  1 \\ 15\end{matrix}\right)\] is this the answer?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1what kind operations there, add, subtrac, or multiplication or division ?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1is it like a+b+c+d+e+f=15 ? with a,b,c,d,e, and f are natural numbers

giovkast
 2 years ago
Best ResponseYou've already chosen the best response.0discrete math, ow sorry its addition

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1hehe... i have guessed actually, i will use the formula : dw:1355741391689:dw

giovkast
 2 years ago
Best ResponseYou've already chosen the best response.0why did you use (15  1)?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1wait... looks i have mistaken

giovkast
 2 years ago
Best ResponseYou've already chosen the best response.0what did you do wrong then, exactly?

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1ok, for the first... i have mistaken after i do some experiments, it shoulde be dw:1355743741310:dw

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1let's discuss for simple example below : a+b+c=6, for a,b,c are natural numbers. # if a=1, then b+c=5 or c=5b to get c be integer , so satisfied for b=1,2,3,4 (there are 4 ways) # if a = 2, then b+c=4, or c=4b to get c be integer , so satisfied for b=1,2,3, (there are 3 ways) # if a = 3, then b+c=3, or c=2b to get c be integer , so satisfied for b=1,2, (there are 2 ways) # if a = 4, then b+c=2, satisfied just for b=1 and c=1 ( 1 way) so, the total ways = 4+3+2+1 = 10 it just similar by C(61, 31) = C(5,2) = 10

giovkast
 2 years ago
Best ResponseYou've already chosen the best response.0there are 6 x's, from x1 till x6 and together they add up to 15

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1with same idea, if given the problem : a+b+c+d=8 so, the total ways = C(81,41) = C(7,3) = 35 ways btw, i have done it by manual also like the first ^ (the answer is same)

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1yeah, like i said before it will be C(151,61) = C(14,5) = 14!/(9!5!) = ....

RadEn
 2 years ago
Best ResponseYou've already chosen the best response.1but, this method will be different, if a,b,c,d,... are the whole numbers :) thanks for ur question, i become more knowing for this problems ......

giovkast
 2 years ago
Best ResponseYou've already chosen the best response.0thank you very much for the explanation
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.